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Dmitriy789 [7]
2 years ago
5

+

Chemistry
2 answers:
Alexxx [7]2 years ago
7 0
The correct awnser is A- 0.174
Alex2 years ago
6 0

Answer: 0.714 moles of PbI_2 will be produced from 237.1 g of potassium iodide

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of potassium iodide}=\frac{237.1g}{166g/mol}=1.428moles

The balanced chemical reaction is:

Pb(NO_3)_2+2KI\rightarrow PbI_2+2KNO_3

According to stoichiometry :

2 moles of KI produce =  1 mole of PbI_2

Thus moles of KI will require=\frac{1}{2}\times 1.428=0.714moles  of PbI_2

Thus 0.714 moles of PbI_2 will be produced from 237.1 g of potassium iodide

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