Dilution is the process of “lowering the concentration of a solute in a solution by simply adding more solvent to the solution, such as water.” Diluting a solution entails adding more solvent without adding more solute.
<h3>How do you do dilution in math?</h3>
The number of dilutions is equal to the number of times the dilution factor will be multiplied by itself to equal the starting concentration divided by the final concentration. So with a dilution factor of 10, 10 to the X power is equal to the starting concentration divided by the final concentration.
<h3>How do you find the dilution of a solution?</h3>
You can solve for the concentration or volume of the concentrated or dilute solution using the equation: M1V1 = M2V2, where M1 is the concentration in molarity (moles/Liters) of the concentrated solution, V2 is the volume of the concentrated solution, M2 is the concentration in molarity of the dilute solution.
Learn more about dilution here:
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brainly.com/question/1553819</h3><h3 /><h3>#SPJ4</h3>
Answer:
so the correct answer would be the 3rd one.
26 proton, 32 neutrons, 26 electrons.
Explanation:
Protons and electrons are the same, which is also the same as the atomic number. in that case that would be 26.
Therefore, proton=electron =26
for neutron, you just have to subtract the mass number to the electron/proton.
n = m - e
n= 58-26
neutron =32.
Hope that helps.
Answer:
<em>forms when a neutron changes into a proton and a high-energy electron .</em>
<em>hope this helps</em><em> </em><em><</em><em>3</em>
Answer:
By reacting carbon monoxide and hydrogen the formation of methanol takes place, the reaction is,
CO(g)+2H₂(g)⇔CH₃OH (g)
Based on the given reaction, one mole of methanol is obtained by reacting one mole of carbon monoxide (CO) with the two moles of hydrogen (H₂). It is mentioned in the question that for the reaction 500 mol of carbon monoxide and 750 moles of hydrogen are present.
Therefore for 500 moles of carbon monoxide, there is a requirement of 2 × 500 moles of hydrogen, which is equivalent to 1000 moles of hydrogen (H₂). However, only 750 moles of hydrogen is present. Therefore, the limiting reactant in the given case is H₂. The present moles of H₂ will react with 0.5 × 750 moles of CO = 375 mole of CO
The additional or excess concentration of CO, which is the excess reactant will be, 500-375 = 125 moles.
