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Veronika [31]
3 years ago
13

Solve for z w=x+y/zplease help​

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer:

your answer would be z= y over w - x

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Solve the x to the nearest tenth​
Nezavi [6.7K]

Answer:

x=11.2

Step-by-step explanation:

So, to solve for x you have to use pythag Theorem. X is the hypotenuse  

If you separate this shape into two parts, splitting the slant portion and the rectangle part. You will have a right triangle, and then you would find all the legs of the triangle.

The shorter leg, which is on the left side. Since the left side including the slanted part is 13 and we had to split the shape the shorter leg would equal 5

13-8=5.

And since the longer leg has the same length as the rectangle, which is 10. You would take both these numbers.

then, Square them and add them. So, 5x5=25

and 10x10=100

100+25=125 afterwards you find the square root. \sqrt{125}=11.18

7 0
3 years ago
HURRY PLEASEEEEEEEEEEE. A coordinate plane. The point (5, 5) is in Quadrant . The point (3, –2) is in Quadrant . The point (–4,
iVinArrow [24]

Answer:

point (5, 5) is in Quadrant: I  (1)

point (3, –2) is in Quadrant: IV   (4)

The point (–4, –4) is in Quadrant: III   (3)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 2. check your answer by noting that the curve is
professor190 [17]
Ok, here we go.  Pay attention.  The formula for the arc length is AL= \int\limits^b_a { \sqrt{1+( \frac{dy}{dx})^2 } } \, dx.  That means that to use that formula we have to find the derivative of the function and square it.  Our function is y = 4x-5, so y'=4.  Our formula now, filled in accordingly, is AL= \int\limits^2_1 { \sqrt{1+4^2} } \, dx (that 1 is supposed to be negative; not sure if it is til I post the final answer).  After the simplification we have the integral from -1 to 2 of \sqrt{17}.  Integrating that we have AL= \sqrt{17}x from -1 to 2.  2 \sqrt{17}-(-1 \sqrt{17} ) gives us 3 \sqrt{17}.  Now we need to do the distance formula with this.  But we need 2 coordinates for that.  Our bounds are x=-1 and x=2.  We will fill those x values in to the function and solve for y.  When x = -1, y=4(-1)-5 and y = -9.  So the point is (-1, -9).  Doing the same with x = 2, y=4(2)-5 and y = 3.  So the point is (2, 3).  Use those in the distance formula accordingly: d= \sqrt{(2-(-1))^2+(3-(-9))^2} which simplifies to d= \sqrt{9+144}= \sqrt{153}.  The square root of 153 can be simplified into the square root of 9*17.  Pulling out the perfect square of 9 as a 3 leaves us with 3 \sqrt{17}.  And there you go!
5 0
3 years ago
If the price showing on the pump is 3.799,what is the price per gallon to the nearest cent?
Lera25 [3.4K]

Answer:

3.80

Step-by-step explanation:

7 0
3 years ago
Given: f(n) = 3n-5 and g(n) = 2n-1<br>Find: (fog)(5​
laiz [17]

Answer:

22

Step-by-step explanation:

So we have the two functions:

f(n)=3n-5\text{ and } g(n)=2n-1

And we want to find (fog)(5). This is the same as:

(f\circ g)(5)=f(g(5))

So, find g(5) first:

g(5)=2(5)-1\\

Multiply and subtract:

g(5)=10-1=9

So, we can substitute:

f(g(5))=f(9)

Find the value:

f(9)=3(9)-5

Multiply and subtract:

f(9)=27-5=22

So:

(f\circ g)(5)=22

And we're done!

4 0
3 years ago
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