Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
Answer:
find value of X and y and you can get answers
Yes. As long as it is linear, it will be continuous no matter the numbers. Now, I have no idea what a "real" number is, but I hope this helped.
Answer:
(Second Option) = g of x equals the quantity x squared minus 5x plus 7 end quantity divided by the quantity x minus 3 end quantity
Step-by-step explanation:
A rational function contains a polynomial in both the numerator and the denominator. This answer fits that requirement.
