How many elements are in N2 and how many atoms are in N2?

A compound is made of 49.31% C, 43.79% 0 and the rest hydrogen. The molar

Alexeev081 [22]

Explanation:

49.31 + 43.79 = 93.10

finding the percentage of hydrogen in the compound hence 100-93.10 =6.9

therefore 6.9 percent of hydrogen is present in the compound

assuming that the compound is in 100 g so the elements present would be 49.31g of C , 43.79g of O and 6.9g of H

no. of moles of C = given mass÷molar mass

= 49.31 ÷ 12

=4.11 mol

no of moles of O = givem mass ÷molar mass

=43.79÷ 16

=2.73 mol

no. of moles of H =6.9÷1

=6.9 mol

dividing the no. of moles of each element by the least count of the elemnt to get the ratio of the simple whole numbr

therefore

so by dividing we get 1:1:2 of C:O:H

the empirical formula is CH2O

empirical formula mass of CH2O IS

= (12)+(2×1)+(16)

= 12+2+16

=30 G/MOL

n= molar mass of the compound ÷ empirical formula mass of the compound

so, n= 146.1 ÷30

n=5

molecular formula = n×empirical formula

molecular formula= 5×CH2O

molecular formula=C5H10O5 (ribose is the compound)

8 0

2 years ago

Which process is a chemical change?

Vinvika [58]

A. is the correct answer.

8 0

3 years ago

Read 2 more answers

In a certain chemical reaction, 2 solid Mg atoms bond with O2 gas to produce solid

soldier1979 [14.2K]

Answer:

Option B. 2Mg(s) + O2 (g) —> 2MgO (s)

Explanation:

From the question given above,

We were told that:

2 solid Mg atoms bond with O2 gas to produce solid MgO.

This can be represented by an equation as follow:

2Mg(s) + O2 (g) —> MgO (s)

Next, we shall balance the above equation as follow:

2Mg(s) + O2 (g) —> MgO (s)

There are 2 atoms of Mg on the left side and 1 atom on the right side. It can be balance by putting 2 in front of MgO as shown below:

2Mg(s) + O2 (g) —> 2MgO (s)

Now, the equation is balanced.

8 0

4 years ago

Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and

N76 [4]

Answer:

Oxidizing agent - CrO4^2-

Reducing agent- N2O

Explanation:

Let us look at the equation closely;

CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]

The reduction half equation is;

CrO4^2- (aq) + 3e -------->Cr^3+ (aq)

Oxidation half equation is;

3N2O(g) ------>3 NO(g) +3 e

Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.

8 0

3 years ago

4,600,000,000,000 in scientific notation

BabaBlast [244]

4.6to the twelth power plus ten or something like that it has been a while since I have done the scientific notation but where ever you put in the number of zeros. is twelve

6 0

3 years ago