What is the molar mass of copper (III) nitrate (Cu(NO3)3)?

Container A holds 717 mL of an ideal gas at 2.80 atm. Container B holds 174 mL of a different ideal gas at 4.30 atm. Container A

horsena [70]

Answer:

3.09 atm

Explanation:

Given that:

Volume of container A = 717 mL

Pressure of container A = 2.80 atm

Volume of container B = 174 mL

Pressure of container B = 4.30 atm

Now, if the valve are being removed and the gases are allowed to mix together; then

The total final pressure can be calculated by using the formula:

$P_f = \dfrac{P_AVA+P_BV_B}{V_A+V_B}$

$P_f = \dfrac{2.80*717+4.30*174}{717+174}$

$P_f = \dfrac{2007.6+748.2}{891}$

$P_f = \dfrac{2755.8}{891}$

$\mathbf{P_f =3.09 \ atm}$

4 0

3 years ago

Does this equation follow the laws of conservation of mass? why?

Marizza181 [45]

Answer:

Yes

Explanation:

Chemical equation:

CuO + H₂ → Cu + H₂O

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

For example:

In given reaction:

CuO + H₂ → Cu + H₂O

there are 1 copper atoms, one oxygen atoms and two hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

4 0

3 years ago

Balance each of the following in BASE: Show work

kupik [55]

Answer : The balanced chemical equation in a basic solution are,

(A) $2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2$

(B) $2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-$

(C) $4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3$

(D) $Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-$

Explanation :

(A) The given chemical reaction is :

$CrO_4^{2-}(aq)+Cu(s)\rightarrow Cr(OH)_3(s)+Cu(OH)_2(s)$

The oxidation-reduction half reaction will be :

Oxidation : $Cu\rightarrow Cu^{2+}+2e^-$

Reduction : $CrO_4^{2-}+4H_2O+3e^-\rightarrow Cr^{3+}+8OH^-$

In order to balance the electrons, we multiply the oxidation reaction by 3 and reduction reaction by 2 then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr^{3+}+16OH^-+3Cu^{2+}$

or,

$2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2$

(B) The given chemical reaction is :

$NO_2(g)\rightarrow NO_3^-(aq)+NO_2^-(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $NO_2+2OH^-\rightarrow NO_3^-+H_2O+1e^-$

Reduction : $NO_2+1e^-\rightarrow NO_2^-$

The electrons in both the reactions are balanced. Now added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-$

(C) The given chemical reaction is :

$Zn(s)+NO_3^-(aq)\rightarrow Zn(OH)_4^{2-}(aq)+NH_3(g)$

The oxidation-reduction half reaction will be :

Oxidation : $Zn+4OH^-\rightarrow [Zn(OH)_4]^{2-}+2e^-$

Reduction : $NO_3^-+6H_2O+8e^-\rightarrow NH_3+9OH^-$

In order to balance the electrons, we multiply the oxidation reaction by 4 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3$

(D) The given chemical reaction is :

$Br_2(l)\rightarrow BrO_3^-(aq)+Br^-(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $Br_2+12OH^-\rightarrow 2BrO_3^-+6H_2O+10e^-$

Reduction : $Br_2+2e^-\rightarrow 2Br^-$

In order to balance the electrons, we multiply the reduction reaction by 5 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

$Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-$

7 0

3 years ago

What is the break down of food into energy

AnnyKZ [126]

it is nutrients that's it

3 0

4 years ago

Brainliest for the best answer and it has to be in ur own words pls and thx

Natasha_Volkova [10]

Answer:

This energy comes from the food we eat. Our bodies digest the food we eat by mixing it with fluids (acids and enzymes) in the stomach. When the stomach digests food, the carbohydrate (sugars and starches) in the food breaks down into another type of sugar, called glucose.

Explanation:

I hope this helps.

8 0

3 years ago

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