Area of Big Rectangle Area of Small Rectangle
A = L x w A = L x w
= (25 + 2w)(10 + 2w) = 25 x 10
= 250 + 50w + 20w + 4w² = 250
Big - Small
74 = 250 + 70w + 4w² - 250
74 = 4w² + 70w
0 = 4w² + 70w - 74
= 2(2w² + 35w - 37)
= 2[2w² -2w | +37w - 37]
= 2[2w(w - 1) | +1(w - 1)]
= 2(2w + 1)(w - 1)
0 = 2 0 = 2w + 1 0 = w - 1
FALSE so disregard w = -1/2 w = 1
NEGATIVE so disregard
Answer: 1 meter
1. plug in the numbers for the variables, like this: 9(-5)+18(-1)
2. solve
Hopefully this helps! Let me know if you need more explanation.
Answer:
.b. It is one‐half as large as when n = 100.
Step-by-step explanation:
Given that a simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and a standard deviation of 3 hours.
i.e. s = 0.3
we obtain se of sample by dividing std devitation by the square root of sample size
i.e. s= 
when n =100 this = 0.3 and
when n =400 this equals 0.15
We find that when sample size is four times as large as original, std deviation becomes 1/2 of the original
Correction option is
.b. It is one‐half as large as when n = 100.
Answer:
3
Step-by-step explanation:
3 pounds were picked per hour