Answer:
5280people
Step-by-step explanation:
Given parameters:
Percentage increase of population = 25%
Population now = 6600
Unknown:
Population last year = ?
Solution:
Let the population last year = y;
Then;
Percentage of last years population plus the population of last year should give us this year's population;
(
of y) + y = 6600
0.25y + y = 6600
1.25y = 6600
y = 
= 5280people
Last year, there was 5280people in the locality.
This is what I’m trying to figure out
Answer:
The answer is C.
Step-by-step explanation:
You might have to ask the question again, i’m jot sure what exactly the question requires
Answer:
C. Quadratic model
Step-by-step explanation:
Determine what type of model best fits the given situation: Farmer Joe has 1,000 bushels of corn to sell. Presently the market price for corn is $5.00 a bushel. He expects the market price to increase by $0.15 per week. For each week he waits to sell, he loses ten bushels due to spoilage. A. none of these B. exponential C. quadratic D. linear
Given:
The quantity of corn Farmer Joe has to sell = 1,000 bushels
The present market price for corn = $5.00 a bushel
The amount by which he expects the market price to rise per week =$0.15
The number of bushels lost to spoilage per week = 10
The price of the corn per bushel with time = 5 + 0.15×t
The amount of corn left with time= 1000 - 10×t
Where;
t = Time in minutes
Value of the corn = Amount of corn left × Price of corn
Value of the corn = (1000 - 10×t) × (5 + 0.15×t)
=(1000-10t) × (5+0.15t)
=5,000 + 150t - 50t - 1.5t²
= -1.5t² +100t + 5000
Value of the corn= -1.5t² +100t + 5000.
It is a quadratic model
