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bonufazy [111]
3 years ago
9

When x = 8, y = 20. Find y when x = 42

Mathematics
2 answers:
GenaCL600 [577]3 years ago
4 0
8x20
42xy
cross multiply both the equation 
8y=42*20
8y=840
y=840/8
y=105
snow_tiger [21]3 years ago
3 0
The answer that I got was y=105
     
Hope this helps!
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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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The sum of 2 numbers is 50. The sum of 1/4 of the first number and 2/3 of the second number is 25.What are the numbers?
tino4ka555 [31]

Answer:

First number: 20

Second number: 30

Step-by-step explanation:

First#:   x

Second#:   y

Constraints:

   x + y = 50      

   1/4x + 2/3y = 25

Isolate variable y:

   x + y = 50    

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 -1/4x - 1/4y = -12.5

  Add equations the two equations to eliminate x:

    -1/4x - 1/4y = -12.5

     1/4x + 2/3y = 25

  _________________

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           5y = 150

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Substitution to find x:

       x + y = 50  

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What is 123+3321= ??
Vedmedyk [2.9K]

Answer:

3444

Step-by-step explanation:

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