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bonufazy [111]
3 years ago
9

When x = 8, y = 20. Find y when x = 42

Mathematics
2 answers:
GenaCL600 [577]3 years ago
4 0
8x20
42xy
cross multiply both the equation 
8y=42*20
8y=840
y=840/8
y=105
snow_tiger [21]3 years ago
3 0
The answer that I got was y=105
     
Hope this helps!
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Can someone help me! Please
likoan [24]

Answer:

4c - 2

Step-by-step explanation:

Add up all the terms to find the perimeter.

2c + 2(c - 1)

2c + 2c - 2

4c - 2

Therefore, the perimeter is 4c - 2.

5 0
3 years ago
Need help with the picture
BaLLatris [955]

Answer:the y=x graph will have a slope of positive one and the y intercept would be 0. The y=-x+4 graph will have a slope of negative one ( line going down) and have a y intercept of 4

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Calculate the perimeter and area of the triangle formed by the coordinates K (-4,-1) ,L(-2, 2), and M (3,-1).
Y_Kistochka [10]

Perimeter = 16.4 units

Using the heron's formula, Area ≈ 10.4 units².

<h3>What is the Heron's Formula?</h3>

The heron's formula is used to find the area of a triangle with known side lengths of all its three sides, a, b, and c. The heron's formula is given as: Area = √[s(s - a)(s - b)(s - c)], where s = half the perimeter of the triangle

s = (a + b + c)/2.

Given the following:

K (-4,-1) ,

L(-2, 2),

M (3,-1)

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, to find KL, LM, and KM.

KL = √[(−2−(−4))² + (2−(−1))²]

KL = √13 ≈ 3.6 units

LM = √[(−2−3)² + (2−(−1))²]

LM = √34 = 5.8 units

KM = √[(−4−3)² + (−1−(−1))²]

KM = √49 = 7 units

Perimeter = 3.6 + 5.8 + 7 = 16.4 units

Semi-perimeter (s) = 1/2(16.4) = 8.2 units

KL = a ≈ 3.6 units

LM = b = 5.8 units

KM = c = 7 units

s = 8.2

Plug in the values into √[s(s - a)(s - b)(s - c)]

Area = √[8.2(8.2 - 3.6)(8.2 - 5.8)(8.2 - 7)]

Area = √[8.2(4.6)(2.4)(1.2)]

Area = √108.6336

Area ≈ 10.4 units²

Learn more about heron's formula on:

brainly.com/question/10713495

#SPJ1

8 0
1 year ago
??????????????????????????
Umnica [9.8K]

Solution:

<em>Simple Interest = Principal Amount × Rate of Interest/100 × Time</em>

Here, Principal Amount = $6000

Rate of Interest =  6%

Time = 4 years

Simple Interest = 6000 × 6/100 × 4 = <em>$1440</em>

3 0
2 years ago
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