For a relation to be a function it must be
relation is not a function.
In the above options, C is
relation therefore cannot be a function.
The reason is that 3 alone maps onto -2 and 5, in the ordered pairs (3,-2) and (3,5). This disqualifies it from being a function.
Hence the graph of this relation will not pass the vertical line test
Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
Slope intercept form:
Y = mx + b
m = slope, b = y intercept
Given the slope of 4
Y = 4x + b
Plug in the point (3,8)
8 = 4(3) + b
8 = 12 + b, b = -4
Y intercept = -4
Solution: y = 4x - 4
Okay so this is a wild guess but I would say 12. The whole angle is 90, but only 1/3 of that is in the smaller portion of the triangle. So, I assumed that 1/3 of the length of the whole triangle. Three times 6 is 18 and minus AD is 12. So BD=12? This is my best guess hope it helps
Answer:
B. [-1, ∞).
Step-by-step explanation:
g(x) = 3|x − 1| − 1
When x = 1 g(x) = 3(0) - 1 = -1.
As all negative vales of x will give positive values of |x - 1| then g(x) = -1 is its minimum value. The graph will be shaped like a letter V with the vertex at (1,-1).
Therefore the range is [-1, ∞).
