What is the slope of the line that contains these points?

A football player punts a ball. The path of the ball can be modeled by the equation y = –0.004x2 + x + 2.5, where x is the horiz

Galina-37 [17]

The answer is 252.5 ft

y = –0.004x² + x + 2.5
Let's take y = 0 and we'll get the quadratic equation:

–0.004x² + x + 2.5 = 0
The general formula for quadratic equation is:
ax² + bx + c = 0

a = -0.004
b = 1
c = 2.5

$x_{1,2} = \frac{-b+/- \sqrt{ b^{2}-4ac} }{2a} =\frac{-1+/- \sqrt{ 1^{2}-4*(-0.004)*2.5} }{2*(-0.004)} = \frac{-1+/- \sqrt{1+0.04} }{-0.008} = \\ 
=\frac{-1+/- \sqrt{1.04} }{-0.008} = \frac{-1+/-1.02}{-0.008}$

$x_1=\frac{-1+1.02}{-0.008} = \frac{0.02}{-0.008} = -2.5 \\ 
x_2=\frac{-1-1.02}{-0.008} = \frac{2.02}{-0.008} = 252.5$

Since distance cannot be negative (x1), the correct answer is x2 = 252.5 ft

5 0

2 years ago

Read 2 more answers

Which of the following is a like term of -5.92?

olga_2 [115]

The answer to this question is c

3 0

3 years ago

Read 2 more answers

Helpppp meeeee outttttt pleaseeeee ASAPPPP!!!!

Ilya [14]

Answer:

$\boxed{\sf sin\ C =\frac{40}{41}}$

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

$\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}$

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

$\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}$

Substitute the respective values ,

$\sf\longrightarrow \boxed{\blue{\sf sin\ C =\dfrac{40}{41}}}$

Hence the required answer is 40/41.

6 0

2 years ago

Easy quick stuff pls Evaluate 11 - 19 - 4 - (-8). -20 -4 -26 -2

slamgirl [31]

Answer:

Step-by-step explanation:

11 - 19 - 4 - (-8) =

11 - 19 - 4 + 8 =

- 23 + 19 =

- 4 <===

5 0

2 years ago

QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Vlad1618 [11]

Complete Question

Table of Annual CPI values

2003-184.00

2004-188.90

2005-195.3

2006-201.6

2007-207.342

2008-215.303

2009-214.537

2010-218.056

2011-224.939

2012-229.594

2013-232.957

2014-236.736

QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Answer:

$C=27535.5881128$

Step-by-step explanation:

From the question we are told that

CPI for 2003(index)=2003-184.00

CPI for 2013(index)=2013-232.957

Starting salary in 2013 at $34,862

Generally comparable starting salary C is given as

$C=\frac{starting salary}{CPI for 2013(index} *CPI for 2003(index)$

$C=\frac{34,862}{232.957} *184$

Therefore C the comparable starting salary is givrn to be

$C=27535.5881128$

$C=27536 appro$

8 0

2 years ago