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3 years ago

Can someone please help me answer this?

Mathematics

1 answer:

ycow [4]3 years ago

7 0

Answer:

5 +8=x+3+2x

13=3x+3

13-3=3x

10=3x

x=10 divided by 3

x=3⅓

approximately 4

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Suppose you have rolled a six-sided die fifty times and recorded the result of each roll.

a_sh-v [17]

Using it's concept, it is found that the relative frequency probability of rolling an even number based on this experiment is $\frac{11}{25}$ .

A relative frequency is the number of desired outcomes divided by the number of total outcomes.

In this problem:

50 dices are thrown, hence $T = 50$ .
22 resulted in an even number, hence $D = 22$

The relative frequency is given by:

$f = \frac{D}{T} = \frac{22}{50} = \frac{11}{25}$

A similar problem is given at brainly.com/question/20630951

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3 years ago

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harkovskaia [24]

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3 years ago

Read 2 more answers

Solve for m. -5<3+m

Firlakuza [10]

-5 < 3 + m subtract 3 from both sides

-5 - 3 < 3 - 3 + m

-8 < m → m > -8

8 0

3 years ago

Read 2 more answers

The notation f:S→T denotes that f is a function, also called a map , defined on all of a set S and whose outputs lie in a set T

AnnyKZ [126]

Answer:

There are many. Two examples are

$f(x) = x, \\f(x) = x^3$

Step-by-step explanation:

There are many examples. The simplest is

1 -

$f(x) = x$

It is trivial that

$\text{if \,\,\,\,} f(x) = f(y) \,\,\,\,\,\text{then} \,\,\,\,\, x=y$

2 -

$f(x) = x^3$

That function is injective as well.

$\text{if \,\,\,\,} x^3 = y^3 \,\,\,\,\,\text{then} \,\,\,\,\, x=y$

An example of a function that is NOT injective is

$f(x) = x^2$

Notice that

$f(-2) = (-2)^2 = 2^2 = 4$

4 0

3 years ago

Two vertical poles of length 10 and 12 feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the

Marat540 [252]

Answer:

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft$

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

$x^{2} +10^{2}=L_{1} ^{2} \\x^{2} + 100 = L_{1} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\ \sqrt{x^{2}+100}= L_{1}$

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

$(17-x)^{2}+12^{2}=L_{2} ^{2} \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}$

Take the square root of both sides

$\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}} \\\sqrt{x^{2}-34x+433}=L_{2}$

Amount of cable used, L = L1 + L2

$L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}$

3 0

3 years ago