Find the approximate value of each trigonometric function.
2 answers:
IDENTITY:
sinθ = - tanθ/√(1 + tan²θ)
cosθ = - 1/√(1 + tan²θ)
<h3>__________________________________________</h3>
ANSWER:
We know that in III quadrant, sine and cosine both are negative.
sinθ = - 3.454/√(1 + 3.454²)
cosθ = - 1/√(1 + 3.454²)
<h3>__________________________________________</h3>
Answer:
<u>Given</u>
- tanθ = 3.454
- θ is in the III quadrant
We know in the III quadrant both sine and cosine are negative.
<u>Use the following identities to get values of sinθ and cos θ</u>
- sinθ = - tanθ/√(1 +tan²θ)
- cosθ = - 1/√(1 +tan²θ)
<u>Substitute the value of tanθ and find sine and cosine:</u>
- sinθ = - 3.454/√(1 + 3.454²) = - 0.961
- cosθ = - 1/√(1 + 3.454²) = - 0.278
You might be interested in
Sally paid $3.82 while Martha paid $1.82 (which makes a total of $5.64 and shows that Sally paid $2 more than Martha)
Answer:
u = 5 and 2/3
Step-by-step explanation:
Answer:
52, 60, 68, 76..
Step-by-step explanation:
(15, -8) :)
From C to midpoint you do (+10, -7), so you have to do that again to get to D
1.) 1.5m/8m= fg/32m
2.) 1.5 (32)= 8m * fg
3.) 1.5 (32)/8m= fg
4.) 6m = fg
Im pretty sure that's right