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Flauer [41]
3 years ago
8

Use coulomb\'s law to calculate the energy of a magnesium ion and an oxide ion at their equilibrium ion-pair separation distance

.
Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
6 0

We know that

F = k * q1 * q2 / d^2

Force of attraction F

K = 8.99 x 10^9

q1 = charge on Mg = +2  = 2 X 1.9 x 10^-19 C

q2 = charge on O = -2 = 2 X 1.9 x 10^-19 C

d = distance between two ions = 72 + 140 pm = 212 pm

Force = 8.99 x 10^9 X 2 X 1.9 x 10^-19 C X 2 X 1.9 x 10^-19 C / (212 X 10^-12 )^2

Force = 0.002889 X 10^-5 = 2.889 X 10^-8 N

sammy [17]3 years ago
5 0

The energy required to separate the ion pair = 4.297×10^(−19)J .

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Answer:

2 NO (g) → N2 (g) + O2 (g)

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The ΔH for the reaction is -103.4 kJ

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What is thermal equilibrium? equal temperature equal heat equal thermal energy equal conductivity
Margarita [4]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

I believe the answer would be A. equal temperature

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6 0
3 years ago
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72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
How many seconds would it take to deposit 17.3 g of ag (atomic mass = 107.87) from a solution of agno3 using a current of 10.00
Brums [2.3K]
Data Given:

Time = t = ?

Current = I = 10 A

Faradays Constant = F = 96500

Chemical equivalent = e = 107.86/1 = 107.86 g

Amount Deposited = W = 17.3 g

Solution:
             According to Faraday's Law,

                                          W  =  I t e / F

Solving for t,

                                          t  =  W F / I e
Putting values,
                                          t  =  (17.3 g × 96500) ÷ (10 A × 107.86 g)

                                          t  =  1547.79 s

                                          t  = 1.54 × 10³ s
5 0
2 years ago
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