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Flauer [41]
3 years ago
8

Use coulomb\'s law to calculate the energy of a magnesium ion and an oxide ion at their equilibrium ion-pair separation distance

.
Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
6 0

We know that

F = k * q1 * q2 / d^2

Force of attraction F

K = 8.99 x 10^9

q1 = charge on Mg = +2  = 2 X 1.9 x 10^-19 C

q2 = charge on O = -2 = 2 X 1.9 x 10^-19 C

d = distance between two ions = 72 + 140 pm = 212 pm

Force = 8.99 x 10^9 X 2 X 1.9 x 10^-19 C X 2 X 1.9 x 10^-19 C / (212 X 10^-12 )^2

Force = 0.002889 X 10^-5 = 2.889 X 10^-8 N

sammy [17]3 years ago
5 0

The energy required to separate the ion pair = 4.297×10^(−19)J .

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3 years ago
Calculate the molarity of an hcl solution if a 10.00 ml sample requires 25.24 ml of a 1.600 m naoh solution to be neutralized.
AlladinOne [14]

Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

<u>Step 1:</u> Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

<u>Step 2:</u> The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

C1 * 0.01 = 1.6 * 0.02524

C1 = (1.6*0.02524)/0.01

C1 = 4.04M

The molarity of the HCl solution should be 4.04 M

6 0
3 years ago
Potassium and sodium chloride are similar in charge and they both have the same anion.  When comparing sodium chloride (36 g / 1
lesya [120]
Sodium Chloride has a higher solubility. 
7 0
3 years ago
Could someone help me with all of these questions. Also plz if you don't know the answer plz don't put something that isn't righ
densk [106]
Q3.) acidic
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3 0
3 years ago
GIVING BRAINLIEST!!!!!!!!
Arte-miy333 [17]

Answer:

It can't be done.

Explanation:

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7 0
3 years ago
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