Question

Student Council is selling tickets to the Winter

Answer 1

Answer:

Two possible combinations are;

1) 200 single and 30 couples

2) 150 single and 57 couples

Step-by-step explanation:

The given parameter in the question are;

The cost of ticket per person = $5

The cost of tickets per couple = $8

The minimum worth of tickets to be sold = $1,200

The maximum number of students that can fit in the gym = 500

Let 'x' represent the number of single persons that attend the dance and let 'y' represent the number of couple that attend, we have;

5·x + 8·y ≥ 1,200

x + y ≤ 500

Making 'y' the subject of both equations gives;

y ≥ 150 - 5·x/8

y ≤ 500 - x

From the graph of the inequalities created with Microsoft Excel, we have;

When x = 200, and y = 30, we get;

5 × 200 + 8 × 30 = 1240 > 1200

200 + 30 × 2 = 460 < 500

We also have;

x = 150, and y = 57, we get

Equating both values of 'y', we get;

5 × 150 + 8 × 57 = 1206 > 1200

150 + 57 × 2 = 264 < 500

Therefore, from the acceptable region in the graph, we have the following two possible combinations

1) 200 single and 30 couples

2) 150 single and 57 couples