1) Upward motion
y1 = Vo*t - g(t^2) / 2
2) Downward motion
y2 = D - [Vo*t + g(t^2) / 2]
3) Collision => y1 = y2
y1 = Vo*t - g(t^2) / 2
y2 = D - [Vo*t + g(t^2) / 2]
Vo*t - g(t^2) / 2 = D - [Vo*t + g(t^2) / 2]
Vo*t - g(t^2) / 2 = D - Vo*t - g(t^2)/2
D = 2Vo*t => t = D / (2Vo)
Substitute the value of t in the equation of y1 (it is the same if you do it in the equation of y2)
y1 = Vo*t - g(t^2) / 2 = Vo [D/(2Vo) ] - g [D / (2Vo)]^2 / 2
y1 = D/2 - g(D^2) / 8(Vo ^2)
Answer: y1 = D/2 - g(D^2) / 8(Vo ^2)
Solve -5w<span> = -80 for </span>w<span>.</span>
For a radio station broadcasts at a frequency of 83.8 MHz with a power of 16.5 kW, the number of photons is mathematically given as
P=6.92*10^{29}photon/sec
<h3>What is the number of photons does the antenna of the station emit in each second?</h3>
Generally, the equation for the energy is mathematically given as
E=hf
Therefore
E=6.63*10^{34}*83*10^6
E=5.561*10^26J
In conclusion, the number of photons
P=dN/dt
P=38500/5.561*10^{26}
P=6.92*10^{29}photon/sec
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