Explanation:
Given that,
Mass of the car, m = 710 kg
Speed of the car, v = 23 m/s
Drag force, F = 500 N
(a) Let P is the power is required from the car's engine to drive the car on the level ground. Power is given by :
(b) Let P is the power is required from the car's engine to drive the car on up a hill with a slope of 2 degrees.
At this slope, force will be,
Total force will be :
Power is given by :
or
P = 17 kW
Q = V*C
V = 5.5 Volts
C = 8.00 * 10^-12 Farads
Q = ???
Q = 8.00 * 10^-12 * 5.5
Q = 44.0 * 10^-12 Coulombs
Q = 44.0 picacoulombs.
Its 21!! sorry i was late! :)
Assuming that these protons are on opossite sides of a nucleus, the strong force between them is zero. The magnitude of the repulsive force between them is given by:
Where k is the coulomb constant, e is the proton charge and d its distance of separation. Replacing the given values and solving: