if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the tube?
1 answer:
A 3rd harmonic of a tube open at both ends will have displacement antinodes at both ends.
In a tube of length L with two open ends, the longest standing wave has displacement antinodes (pressure nodes) at both ends. The fundamental or first harmonic is what it is known as. The second harmonic is the longest standing wave in a tube of length L with two open ends.
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Answer:
a) 72.54° and It will take the woman 33.4m
Explanation:
The woman runs with a constant speed V1 = 6m/s
V2 = 20m/s
V1 = V2 cos θ
Cos θ= V1/V2= 6/20
Cos θ= 0.3
Cos^-1 0.3=72.54°
Using Range formular for projectile
R= (V2 Cos θ)/g (V2 Sin θ)^2 +sqrt(V2 Sin θ)^2 + 2gh)
R= (20cos72.54)(2Sin72.54+sqrt(20Sin72.54)^2 + 2×9.8×45
R=33.4m
b )
see the attached file
The average current density in the wire is given by:
where I is the current intensity and A is the cross-sectional area of the wire.
The cross-sectional area of the wire is given by:
where r is the radius of the wire. In this problem, , so the cross-sectional area is
and the average current density is