1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stira [4]
1 year ago
10

if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the tube?

Physics
1 answer:
Katena32 [7]1 year ago
7 0

A 3rd harmonic of a tube open at both ends will have displacement antinodes at both ends.

In a tube of length L with two open ends, the longest standing wave has displacement antinodes (pressure nodes) at both ends. The fundamental or first harmonic is what it is known as. The second harmonic is the longest standing wave in a tube of length L with two open ends.

Learn more about harmonics here brainly.com/question/17315536

#SPJ10

You might be interested in
Which energy changes take place when a pedaling cyclist uses a generator (dynamo) to light his bicycle
Fynjy0 [20]

When the pedaling cyclist uses a generator (dynamo) to light his bicycle lamp, the energy change is from mechanical to electrical.

<h3>Law of conservation of energy</h3>

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

Thus, we can conclude the following as it relates to energy changes;

  • When the pedaling cyclist uses a generator (dynamo) to light his bicycle lamp, the energy change is from mechanical to electrical.

Learn more about conservation of energy here: brainly.com/question/166559

4 0
2 years ago
Read 2 more answers
Which is heavier a pound of bricks or a pound of feather
Shkiper50 [21]

Answer:

pound of bricks

meh wrong ? XD

4 0
2 years ago
Read 2 more answers
Two speakers separated by a distance of 4.40 m emit sound. The speakers have opposite phase. A person listens from a location 3.
Hoochie [10]

Answer:

f = 147.21 Hz

Explanation:

In order to have a destructive interference, as the source emit in opposite phases, the path difference between the distance to the person, measured in a straight line from the speakers, must be equal to an integer number of wavelengths.

We need to know the distance from the listener to the other speaker, located 4.4 m from the one which is directly in front of him, which we can find using Pythagorean theorem, as follows:

l₂ = √(3)²+(4.4)² = 5.33 m

The difference in path will be, then:

d = l₂-l₁ = 5.33 m - 3.00 m = 2.33 m

For the lowest frequency that gives destructive interference, the wavelength will be highest possible, which happens when the distance is just one wavelength.

⇒ d = λ = 2.33 m

In any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

v = λ*f Κ  ⇒ f = v/λ

Taking the speed of sound as 343 m/s, and solving for f, we get:

f= 343 m/s / 2.33 m = 147.21 Hz

3 0
3 years ago
a wire with mass per unit length 75 g/m runs horizontally at right angles to a uniform horizontal 0.12 T magnetic field. what am
Sindrei [870]

Answer:

The amount of current that must flow through the wire for it to be suspended against gravity by magnetic force = 6.125 A

Explanation:

Force on a wire carrying current in an electric field is given by

F = (B)(I)(L) sin θ

For this question,

The magnetic force must match the weight of the wire.

F = mg

mg = (B)(I)(L) sin θ

(m/L)g = (B)(I) sin θ

Mass per unit length = 75 g/m = 0.075 kg/m

B = magnetic field = 0.12 T

I = ?

g = acceleration due to gravity = 9.8 m/s

θ = angle between wire's current direction and magnetic field = 90°

0.075 × 9.8 = 0.12 × I sin 90°

I = 0.075 × 9.8/0.12 = 6.125 A

3 0
3 years ago
A student took a calibrated 250.0 gram mass, weighed it on a laboratory balance, and found it read 266.5 g. What was the student
Kruka [31]

Answer:

B. 6.6%

Explanation:

The percentage error of a measurement can be calculated using the formula;

Percent error = (experimental value - accepted value / accepted value) × 100

In this question, the calibrated 250.0 gram mass is the accepted value while the weighed mass of 266.5 g is the experimental or measured value.

Hence, the percentage error can be calculated thus;

Percent error = (266.5-250.0/250.0) × 100

Percent error = 16.5/250 × 100

Percent error = 0.066 × 100

Percent error = 6.6%

7 0
3 years ago
Other questions:
  • Gravitational force is directly related to mass and inversely related to distance. So the bigger the masses the greater the forc
    10·1 answer
  • A feather will fall through the air more slowly than a brick because of
    7·1 answer
  • In solving for the magnitude of the electric field E⃗(z) produced by a sheet charge with charge density σ, use the planar symmet
    10·1 answer
  • Is nickel coin magnetic?
    12·2 answers
  • Can someone please help me with part a and d
    5·2 answers
  • Help I need to know this answer!!
    11·1 answer
  • Avg velocity definition | Problem Average velocity vectors…
    11·1 answer
  • Draw the electric field line which passes through a circle...​
    8·1 answer
  • Which atom is being researched as a possible ingredient of magnetic soap
    9·1 answer
  • 10. What do you think the effect is of jet airplanes on global warming?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!