The first physicist gets a second physicist to help. They both push on the crate, parallel to the surface of the incline, and it moves at constant speed up the incline. How does the force exerted by the two physicists on the crate compare with the force of friction on the crate
1 answer:
Answer:
F_aplied = fr
Explanation:
Newton's second law states that the force is proportional to the acceleration of the system, as in this case they indicate that the body moves at constant speed, the acceleration is zero, therefore
F_applied - fr = 0
F_aplied = fr
therefore the force applied by people is equal to the friction force
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The pressure will be of 399.17 mmHg.
Explanation:
p1= 754 mmHg
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p2= ?
V2= 8.5 L
p1*V1 = p2*V2
p2= (p1*V1)/V2
p2= 399.17 mmHg
Answer:
s = 23.72 m
v = 21.56 m/s²
Explanation:
given
time to reach the ground (t) = 2.2 second
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u = 0 m/s
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s = 0 + 0.5 × 9.8 × 2.2²
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v = √(2gh)
v = √(2× 9.8 × 23.72)
v = √464.912
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