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natita [175]
3 years ago
7

A football player kicks a ball with an initial velocity of 15 m/s at an angle of 43° above the horizontal. Approximately,

Physics
1 answer:
Charra [1.4K]3 years ago
6 0

Hi there!

The vertical component is the SINE of the velocity vector.

Thus:

v_y = vsin\theta

Plug in the givens:

v_y = 15sin(43) = \boxed{10.23 m/s}

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Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

<h3>What is electric force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

\rm F= K\frac{q_2q_3}{r^2}

\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}

\rm F=  - 1. 1 \times 10^{11 }N

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

brainly.com/question/1076352

4 0
2 years ago
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The solution for this problem is:
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Answer:

Explanation:

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