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djyliett [7]
4 years ago
12

Two separate but nearby coils are mounted along the same axis. A power supply controls the flow of current in the first coil, an

d thus the magnetic field it produces. The second coil is connected only to an ammeter. The ammeter will indicate that a current is flowing in the second coila.only if the second coil is connected to the power supply by rewiring it to be in series with the first coil.
b.only when the current in the first coil changes.

c.whenever a current flows in the first coil.

d.only when a steady current flows in the first coil.
Physics
1 answer:
Anit [1.1K]4 years ago
8 0

Answer:

b.only when the current in the first coil changes.

Explanation:

An induced current flow in the second coil only when there is a change in current in the first cool. A steady current will produce no change in flux (due to magnetic effect of a current) by the first coil, and according to Faraday, induced current is only produced when there is a change in flux linkage.

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Which of Galileo's observations directly disproved Ptolemy's epicycle model of the Solar System, showing that the Sun is at the
Neporo4naja [7]

Answer:

Venus observation.

Explanation:

Galileo had learned regarding the  heliocentric (Sun-centered) idea of Copernicus, and acknowledged it. However, the theory was proven by Galileo's observations of Venus. Galileo concluded that Venus should travel round the Sun, sometimes passing behind and then beyond, instead of directly rotating around the Earth.

8 0
3 years ago
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IgorC [24]

Answer:

because the velocity and mass are more with susan

Explanation:

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5 0
3 years ago
The Global Positioning System (GPS) is a constellation of about 24 artificial satellites. The GPS satellites are uniformly distr
Liono4ka [1.6K]

Answer:

b) 3.72m/s²

c) 9.33*10^5

d) 9.33*10^5

e) 11.85 hrs

Explanation:

a) to confirm that gEarth is about 98 m/s².

Let's use the formula:

gEarth= \frac{G*M}{R^2}

= \frac{6.67*10^-^1^1*5.972*10^2^4}{(6378*10^3)^2}

= 9.78 m/s²

=> 9.8m/s²

b) Given:

m = 6.417*10^2^3

r = 2106 miles

g_Mars = \frac{G*M}{R^2}

= \frac{6.67*10^-^1^1*6.417*10^2^3}{(2106*1.61*10^3)^2}

=3.72 m/s²

c) we use:

F = \frac{G*M*m}{R^2}

=\frac{6.67*10^-^1^1*5.972*10^2^4*1630*10^3}{((20000+6378)*10^3)^2}

= 9.33*10^5 N

d) Let's take the force of gravitybon earth due to satellite as our answer in (c) because the Earth's gravitational force on a GPS satellite and the force of gravity on a GPS satellite on earth are equal and opposite (two mutual forces).

F = 9.33*10^5 N

e) In a circular motion,

Gravitional force = Centripetal force.

\frac{GM*m}{R^2}=\frac{m*v^2}{R}

\frac{GM}{R}= v^2

Solving for v, we have

v= \sqrt{\frac{6*67*10^-^1^1*5.972*10^2^4}{(20000+6278)*10^3}}

v = 3886m/s

Therefore,

v = 2πR/T

3886 = \frac{2*pi*(20000+6378)*10^3}{T}

Solving for T, we have:

T = 42650seconds

Convert T to hours

T = 42650/60*60

T = 11.86hrs

6 0
4 years ago
How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?
tatyana61 [14]
Missing part in the text of the problem: 
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
Q=m C_s \Delta T
where
m=1.8 g is the mass of the water
C_s = 4.18 J/(g K) is the specific heat capacity of the water
\Delta T=2.5 K is the increase in temperature.

Substituting the data, we find
Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E

We know that each photon carries an energy of
E_1 = hf
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
\lambda =  \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz

So, the energy of a single photon of this frequency is
E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J

and the number of photons needed is the total energy needed divided by the energy of a single photon:
N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons
4 0
3 years ago
The process shown in this diagram contributed great amounts of heat to the young planet Earth and is best known as radioactive
Elis [28]
<span>The process shown in this diagram contributed great amounts of heat to the young planet Earth and is best known as radioactive decay. Decay is known to release large amounts of heat. </span>
4 0
3 years ago
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