<span>The lagrangian center of mass between two particles of equal mass can be calculated using the following equation: L=12MV2â’Uext.+Nâ‘i=112mi~v2iâ’Uint. M=â‘mi is the total mass, V is the speed of the center of mass, Uext.=â‘Uext.,i, and ~vi is the speed of the ith particle relative to the center of mass.</span>
Answer:
21.8 m/s
Explanation:
At the top of the hill (crest), there are two forces acting on the motorcycle:
- The reaction force of the road, N (upward)
- The force of gravity, mg (downward)
Since the motorcycle is moving by circular motion, the resultant of these forces will give the centripetal force, so:

where the direction of the weight (mg) is equal to that of the centripetal force, and where
m is the mass of the cycle
g = 9.8 m/s^2 is the acceleration of gravity
v is the speed
r = 48.6 is the radius of the hill
The cycle loses contact with the road when the reaction force becomes zero:
N = 0
Substituting into the equation, we therefore find the maximum speed that is allowed for the cycle before losing constact:

Answer:
Magnitude of angular acceleration = -3.95 rad/s²
Explanation:
Angular acceleration is the ratio of linear acceleration and radius.
That is

Radius = 72 cm = 0.72 m
Linear acceleration is rate of change of velocity.

Angular acceleration

Angular acceleration = -3.95 rad/s²
Magnitude = 3.95 rad/s²
Answer:
The input force that you use on an inclined plane is the force with which you push or pull an object. The output force is the force that you would need to lift the object without the inclined plane. This force is equal to the weight of the object.
Explanation: