A force of 20. Newtons to the left exerted on a cart for 10. Seconds. For what period of time must a 50.-newton force to the rig ht act to produce an impulse of equal magnitude on the cart?
1 answer:
Impulse = (force) x (time) The first impulse was (20 N) x (10 sec) = 200 meters/sec The second one is (50 N) x (time) and we want it equal to the first one, so (50 N) x (time) = 200 meters/sec Divide each side by 50N : Time = 200/50 = <em>4 seconds</em> By the way, the quantity we're playing with here is the cart's <em>momentum</em> .
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