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Svetradugi [14.3K]
3 years ago
8

A force of 20. Newtons to the left exerted on a cart for 10. Seconds. For what period of time must a 50.-newton force to the rig

ht act to produce an impulse of equal magnitude on the cart?
Physics
1 answer:
FinnZ [79.3K]3 years ago
6 0
Impulse = (force) x (time)

The first impulse was (20 N) x (10 sec) = 200 meters/sec

The second one is (50 N) x (time) and we want it equal to the first one, so

(50 N) x (time) = 200 meters/sec

Divide each side by 50N :    Time = 200/50 = <em>4 seconds</em>

By the way, the quantity we're playing with here is the cart's <em>momentum</em>.
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Answer:

The answer is 50 Nm

Explanation:

<h3><u>Given</u>;</h3>
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Here,

W = F • d

W = 50 • 1

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Thus, Work done is 50 Nm

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PART B)

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Answer:

1kg

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