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Svetradugi [14.3K]
3 years ago
8

A force of 20. Newtons to the left exerted on a cart for 10. Seconds. For what period of time must a 50.-newton force to the rig

ht act to produce an impulse of equal magnitude on the cart?
Physics
1 answer:
FinnZ [79.3K]3 years ago
6 0
Impulse = (force) x (time)

The first impulse was (20 N) x (10 sec) = 200 meters/sec

The second one is (50 N) x (time) and we want it equal to the first one, so

(50 N) x (time) = 200 meters/sec

Divide each side by 50N :    Time = 200/50 = <em>4 seconds</em>

By the way, the quantity we're playing with here is the cart's <em>momentum</em>.
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faltersainse [42]
Speed = frequency x wavelength
300,000,000 = 125000 x wavelength
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or 4.1667E-4 meters
4 0
3 years ago
Silver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?
Neko [114]

Answer:

<h3>The answer is 0.54 g/cm³</h3>

Explanation:

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density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{10.5}{19.3}  \\  = 0.54404145...

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<h3>0.54 g/cm³</h3>

Hope this helps you

7 0
3 years ago
A segment of wire carries a current of 25 A along the x axis from x = −2.0 m to x = 0 and then along the y axis from y = 0 to y
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8 0
3 years ago
Work is done on a locked door that remains closed while you try to pull it open. True False.
dsp73

Answer:False

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8 0
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How?? anyone?!...........
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-- find the horizontal and vertical components of F1.

-- find the horizontal and vertical components of F2.

-- find the horizontal and vertical components of F3.

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-- the direction of the resultant is the angle whose tangent is (vertical component/horizontal component), starting from the positive x-direction.
8 0
2 years ago
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