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timofeeve [1]
2 years ago
6

73.5 mol of P4O10 contains how many moles of P ? moles of P:

Chemistry
1 answer:
Sholpan [36]2 years ago
7 0

Answer:

294 moles of P

Explanation:

For every 1 mol of P4O10 contains 4 mol of P

so;

73.5 mol P4O10 × <u> </u><u> </u><u> </u><u> </u><u> </u><u>4 mol P</u><u> </u><u> </u><u> </u><u> </u><u> </u>

1 mol P4O10

= 73.5 × 4

= 294 moles of P

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Answer:

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Explanation:

We are given that

Aqueous solution that contains 22.9% NaOH by mass means

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Using the formula

Number of moles of  NaOH(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}

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n_A=4.279 moles

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=\frac{n_B}{n_B+n_A}

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Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

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