Answer:
Re=2094,76
Explanation:
For a fluid that circulates inside a straight circular pipe, the Reynolds number is given by:

where (using the international measurement system):
- ρ: density of the fluid [kg/m3]
- v: velocity of the fluid [m/s]
- D: diameter of the pipe through which the fluid circulates [m]
- μ: dynamic viscosity [Pa.s]
To solve the probelm, we just need to replace our data using <u>THE CORRECT UNITS</u> in the Reynolds number equation. So we have:
ρ=1051 kg/m3,
v=34,3 cm/s=0,343 m/s
D=2,15 cm = 0,0215 m
μ = 3,7 cp * 10^-3 Pa.s/1 cp = 3,7*10^-3 Pa.s
Replacing in the main equation:

So the Reynolds number is 2094,76 (note that the Reynolds number is a dimensionless quantity).
<u>Answer:</u>
1. A substance that is soluble in two liquids and makes an emulsion last longer is called "Emulsifier".
2. The process that reduces the size of particles so emulsions will last longer is called "Homogenization".
<u>Explanation:</u>
Emulsifiers are additives which enable two liquids to mix around each other. Water and oil separate in a container, for an instance, but using an emulsifier can make the liquids blend along. It is widely used on various foods and beverages. Egg yolks and mustard are a few examples of emulsifiers.
Homogenization is the physical mechanism by which the fat molecules in milk are broken down because then they stay incorporated instead of segregated as cream. Majority of the milk sold in the United States is homogenized.
Hi there, the correct answer to this would be reactivity because color, melting point, and density are all examples of physical properties.
It is hard because we can't get past the crust, Our machines will burn up at the mantle and so will we. The layers go: crust, mantle, outer core, inner core.
Depression in freezing point (Δ
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) =

×m×i,
where,
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= cryoscopic constant =

,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For
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)
Thus, (Δ
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) = 1.86 X 0.0085 X 2 =

Now, (Δ
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) =

- T
Here, T = freezing point of solution

= freezing point of solvent =

Thus, T =

- (Δ

) = -