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zalisa [80]
3 years ago
6

If you know that the period of a pendulum is 1.87 seconds, what is the length of that pendulum? (Assume that we are on Earth and

that gravity is 9.81 meters/second².) Select one of the options below as your answer: A. 0.87 centimeters B. 2.1 meters C. 1.6 meters D. 0.87 meters E. 8.3 meters
Physics
2 answers:
shepuryov [24]3 years ago
8 0

Period of an ideal simple pendulum  =  2π √(L / G)

                                          1.87 = 2π √ (L / 9.81)

Divide each side by  2π :      (1.87 / 2π) = √ (L / 9.81)

Square each side:                (1.87 / 2π)²  =  L / 9.81

Multiply each side by  9.81 :      L = (9.81) (1.87 / 2π)²  = <em> 0.869 meter</em>

                                              Choice 'D' is the closest one.


mote1985 [20]3 years ago
8 0

Answer : The correct option is, (D) 0.87 meters

Solution :

Formula used :

T=2\pi \times \sqrt{\frac{L}{g}}

where,

T = time period of a pendulum = 1.87 seconds

L = length of the pendulum = ?

g = gravity on earth = 9.8m/s^2

Now put all the given values in the above formula, we get the length of the pendulum.

1.87s=2\times \frac{22}{7}\times \sqrt{\frac{L}{9.8m/s^2}}

0.2975=\sqrt{\frac{L}{9.8m/s^2}}

Now squaring on both the sides, we get

L=0.868m=0.87m

Therefore, the length of the pendulum is, 0.87 meters.

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Explanation:

For transformer we know that the working principle is given as

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here we know that

V_1 [tex] = voltage in primary coil[tex]V_2 = 25 V

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8 0
3 years ago
A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. If the speed of the object when
vampirchik [111]

Answer:

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s = 50m ==> s is just an abbreviation for distance, it is conventional.

v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

v^{2} = u^{2} + 2as\\\\=> a = \frac{v^{2} - u^{2}}{2s}\\a = \frac{500^{2} }{2*50}\\a = 2500ms^{-2}

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Answer:

Explanation:

We know that,

Neptune is 4.5×10^9 km from the sun

And given that,

Earth is 1.5×10^8km from sun

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Using Keplers third law

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P(earth)²/a(earth)³ = P(neptune)² / a(neptune)³

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The semi major axis of Neptune is

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