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3 years ago

A 5,257 kg rocket blasts off to the moon with an acceleration of 76 m/s ^2 what is the net force on the rocket

1 answer:

7 0

Newton's subsequent law expresses that power is corresponding to what exactly is needed for an object of consistent mass to change its speed. This is equivalent to that item's mass increased by its speed increase.

We use Newtons, kilograms, and meters each second squared as our default units, albeit any proper units for mass (grams, ounces, and so forth) or speed (miles each hour out of every second, millimeters per second², and so on) could unquestionably be utilized also - the estimation is the equivalent notwithstanding.

Hence, the appropriate answer will be 399,532.

Net Force = 399532

You might be interested in

If Rebecca is traveling at 7 m/s east for 1 hour how much is Rebecca displaced

Mekhanik [1.2K]

Answer:

25.2 km east

Explanation:

The relationship between velocity and displacement is given by:

$v=\frac{d}{t}$

where

v is the velocity

d is the displacement

t is the time

In this problem, we have:

$v=7 m/s$ east is Rebecca's velocity

$t=1 h=60 min=3600 s$ is the time taken

Re-arranging the equation, we can find Rebecca's displacement:

$d=vt=(7 m/s)(3600 s)=25,200 m=25.2 km$

and the direction is same as velocity (east)

3 0

3 years ago

First, you will investigate purely vertical motion. The kinematics equation for vertical motion (ignoring air resistance) is giv

AlladinOne [14]

Answer: It takes 2.85 seconds.

Explanation: according to the question, the kinematics equation for vertical motion is

$y(t) = y_{0} + v_{0} .t - \frac{1}{2} .gt^{2}$

y₀ is the initial postion and equals 0 because it is fired at ground level;

v₀ is the initial speed and eqauls 14m/s;

g is gravity and it is 9.8m/s²;

y(t) is the final position and equals 0 because it is when the pumpkin hits the ground;

Rewriting the equation, we have:

0 + 14t - $\frac{1}{2}.9.8.t^{2}$ = 0

14t - 4.9t² = 0

t(14 - 4.9t) = 0

For this equation to be zero,

t = 0 or

14 - 4.9t = 0

- 4.9t = - 14

t = $\frac{14}{4.9}$

t = 2.86

It takes 2.86 seconds for the pumpkin to hit the ground.

6 0

3 years ago

Water has a mass per mole of 18.0 g/mol, and each water mo- lecule (H2O) has 10 electrons. (a) How many electrons are there in o

Dovator [93]

Answer:

a) There are $3,35*10^{26}$ electrons in a liter of water.

b) The net charge is -53601707,1 C

Explanation:

a) To find out how many electrons are in a liter of water (equivalent to 1000 grams of water), we have to find out how many molecules of water there are and then multiply it by 10 (e- per molecule).

We can find out how many molecules are by finding the number of moles and then multiplying it by Avogadro's number (number of elements per mol):

$e^{-}= \frac{m_{water} }{M_{water} } * Avogadro* \frac{e^{-} }{molecule}= \frac{1000g }{18g/mol} * 6,022*10^{23} * \frac{10e^{-} }{molecule}=3,35*10^{26} e^{-}$

b) As all electrons have the same charge, in order to find the net charge of those electrons we have to multiply the charge of a single electron by the number of electrons:

$Net charge= -1,602*10^{-19} \frac{C}{e^{-} } *3,35*10^{26} e^{-}=-53601707,1 C$

An important clarification is that while the net charge may seem huge, water as a whole is a neutral medium, because there are as many protons as there are electrons, and as they have the same charge, the net charge of water is 0.

8 0

4 years ago

Suppose the earth suddenly came to halt and ceased revolving around the sun. The gravitational force would then pull it directly

AleksAgata [21]

Answer:

613373.65233 m/s

Explanation:

M = Mass of Sun = $1.989\times 10^{30}\ kg$

m = Mass of Earth

v = Velocity of Earth

r = Distance between Earth and Sun = $147.12\times 10^{9}\ m$

$r_e$ = Radius of Earth = $6.371\times 10^6\ m$

$r_s$ = Radius of Sun = $695.51\times 10^6\ m$

In this system it is assumed that the potential and kinetic energies are conserved

$\dfrac{1}{2}Mv_2-\dfrac{GMm}{r_e+r_s}=0-\dfrac{GMm}{r}\\\Rightarrow v=\sqrt{2GM(\dfrac{1}{r_e+r_s}-\dfrac{1}{r})}\\\Rightarrow v=\sqrt{2\times 6.67\times 10^{-11}\times 1.989\times 10^{30}(\dfrac{1}{6.371\times 10^6+695.51\times 10^6}-\dfrac{1}{147.12\times 10^{9}})}\\\Rightarrow v=613373.65233\ m/s$

The velocity of Earth would be 613373.65233 m/s

3 0

3 years ago

A student holds a bike wheel and starts it spinning with an initial angular speed of 9.0 rotations per second. The wheel is subj

zloy xaker [14]

Answer:

T = 0.00889 N*m

Explanation:

Given the initial speed

Vo = 9.0rev/s.

V = 65 rev/10s

V = 6.5 rev/s.

V = Vo + a*t

Solve to acceleration knowing the initial velocity and the velocity at 10 s

6.5 rev/s - 9 rev/s = a*10s

a = -0.25 rev/s^2.

Now the solve the time at stop time so V=0

V = Vo + a*t

0 = 9.0 - 0.25 rev/s *t,

t = 36 s The Stopping time.

36s - 10s = 26s

The torque can be find using the acceleration using the equation

T = I*a

I = 1/2*m*r^2

I = 1/2*0.725kg*(0.315m)^2= 0.0359kg*m^2

T = 0.0359kg*m^2*-0.25rev/s^2

T = 0.00889 N*m

7 0

3 years ago