For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as
Wt=1945.475J
<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>
Generally, the equation for work is mathematically given as
Wt=wac+Wc+Wba
Therefore
Wac=Pa(Vc-Va)=nR(Tc-Ta)
Wac=3(8.314*192)
Wac=4788.864J
Wcb=P1v1-p2v2/v-1
Wcb-3*8.34*108/0.4
Wcb=-6734.34J
Wab=0
In conclusion,
Wt=wac+Wc+Wba
Wt=4788.864J+0+(-6734.34J)
Wt=+1945.475J
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Answer:
139 N
Explanation:
Thats the answer on e2020
They will become identical as if they were never broken