An ideal gas is at a temperature of 320 K. What is the average translational kinetic energy of one of its molecules
1 answer:
Answer:
<em>6.624 x 10^-21 J</em>
<em></em>
Explanation:
The temperature of the ideal gas = 320 K
The average translational energy of an ideal gas is gotten as
=
where
is the average translational energy of the molecules
= Boltzmann constant = 1.38 × 10^-23 m^2 kg s^-2 K^-1
T is the temperature of the gas = 320 K
substituting value, we have
=
= <em>6.624 x 10^-21 J</em>
You might be interested in
Answer:
Explanation:
Calculating the exit temperature for K = 1.4
The value of is determined via the expression:
where ;
R = universal gas constant =
k = constant = 1.4
The derived expression from mass and energy rate balances reduce for the isothermal process of ideal gas is :
------ equation(1)
we can rewrite the above equation as :
where:
Thus, the exit temperature = 402.36 K
The exit pressure is determined by using the relation:
Therefore, the exit pressure is 17.79 bar