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grin007 [14]
3 years ago
7

Use the IUPAC nomenclature rules to give the name for this compound - CrPO4.

Chemistry
1 answer:
MrRissso [65]3 years ago
7 0

Answer:

i need help

Explanation:

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Physical Science Structures and Properties of Matter Portfolio
daser333 [38]

Answer:

true

Explanation:

8 0
3 years ago
Help me. correct answer will be marked as brnlst
Vlada [557]

Answer:

PCI3

Explanation:

It does not obey the octet rule on the nitrogen atom.

5 0
2 years ago
Read 2 more answers
State the basicity of this acid HCOOH​
Katena32 [7]

Answer:

The basicity of HCOOH (otherwise known as formic acid) is 1

Explanation:

5 0
3 years ago
a 125 g chunk of aluminum at 182 degrees Celsius was added to a bucket filled with 365 g of water at 22.0 degrees Celsius. Ignor
Diano4ka-milaya [45]
<h3>Answer:</h3>

32.98°C

<h3>Explanation:</h3>

We are given the following;

Mass of Aluminium as 125 g

Initial temperature of Aluminium as 182°C

Mass of water as 265 g

Initial temperature of water as 22°C

We are required to calculate the final temperature of the two compounds;

First, we need to know the specific heat capacity of each;

Specific heat capacity of Aluminium is 0.9 J/g°C

Specific heat capacity of water is 4.184 J/g°C

<h3>Step 1: Calculate the Quantity of heat gained by water.</h3>

Assuming the final temperature is X°C

we know, Q = mcΔT

Change in temperature, ΔT = (X-22)°C

therefore;

Q = 365 g × 4.184 J/g°C × (X-22)°C

    = (1527.16X-33,597.52) Joules

<h3>Step 2: Calculate the quantity of heat released by Aluminium </h3>

Using the final temperature, X°C

Change in temperature, ΔT = -(X°- 182°)C (negative because heat was lost)

Therefore;

Q = 125 g × 0.90 J/g°C × (182°-X°)C

  = (20,475- 112.5X) Joules

<h3>Step 3: Calculating the final temperature</h3>

We need to know that the heat released by aluminium is equal to heat absorbed by water.

Therefore;

(20,475- 112.5X) Joules = (1527.16X-33,597.52) Joules

Combining the like terms;

1639.66X = 54072.52

             X = 32.978°C

                = 32.98°C

Therefore, the final temperature of the two compounds will be 32.98°C

7 0
3 years ago
The percent by mass of copper in CuBr2 is Use mc004-1.jpg. 28.45%. 44.30%. 63.55%. 71.55%.
Greeley [361]
First, we must find the total mass of CuBr₂:
Mass = 64 + 2 x 80
Mass = 224

Percentage mass of copper = mass of copper x 100 / total mass
Percentage mass of copper = (64 / 224) x 100
Percentage mass of copper = 28.45%
3 0
2 years ago
Read 2 more answers
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