Answer:

Step-by-step explanation:

Best Regards!
Answer:
From the survey, the following apply to both Junior and Seniors who were asked about their plan towards attending college:
C. Given the student plans to attend college, the probability the student is a junior is 68%.
D. Given the student is a junior, the probability the student plans to attend college is 68%.
F. Events "is a senior" and "plans to attend" are independent.
B. The probability the student plans to attend college is 70%.
Step-by-step explanation:
Answer:
a. mean = 1000
standard deviation = 4358.9
b. expected value of average damage bar Y = 1000
probability bar y exceeds 2000 = 0.011
Step-by-step explanation:
we have p1 = 95%, y1 = 0, p2 = 5%, y2 = 20000
Mean = (0.95 * 0) + (0.05 * 20000)
= 1000
var(y) = E(y²) - E(Y)²
= we solve for E(y)²
= 0²*0.95 + 20000²*0.05
= 0 + 20000000
then the variance of y = 20000000 - 1000²
=20000000-1000000
= $19000000
standard deviation is the square root of variance
= √19000000
= 4358.9
2.
a. Expected value of average is also the mean = 1000
b. we are to find probability that barY exceeds 2000

= 1000/435.889
= 2.29
1-p(z≤2.29)
= 1 - 0.989
= 0.011
so the probability that barY exceeds 2000 is 0.011
1/4b=-3
Solve for b
1/4b *4 = -3*4
b = -3 *4
b = -12
Answer: b = -12
Answer:
83.3%
Step-by-step explanation:
The probability of rolling a 3 on a 6-sided dice is 1/6
Since you don't want a three, there's a 5/6 chance of not rolling a 3
5/6 (use calculator and divede 5 by 6) = 0.833333 (move decimal 2 to the right) = 83.3%
Therefore, the most reasonable answer would be C, 83.3%