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tiny-mole [99]
2 years ago
14

What is the mean, outlier & mean without outlier for 4; 4; 5; 6; 8; 9; 27

Mathematics
1 answer:
aleksley [76]2 years ago
5 0

Answer:

the mean is 9.

Step-by-step explanation:

<h2>mean=<u>4+4+5+6+8+9+27</u></h2>

7

<h2>= <u>63</u></h2><h2> 7</h2><h2> 9 is the answer.</h2>

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Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
coldgirl [10]

Answer:

c is all the points in the open interval (0,25)

Step-by-step explanation:

Here given is a function

f(x) =x, which is continuous  in the interval [0,25] and differentiable in (0,25)

Mean value theorem says there exists at least one c in the interval (0,25) such that

f'(c) = \frac{f(25)-f(0)}{25-0}

We have

f(25)=25 and f(0) = 0\\f'(c) = 1

For the given function

f'(x) =1

Hence we have c equals all the points in the open interval (0,25)

7 0
3 years ago
Can someone please solve this please.
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Answer:

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Step-by-step explanation:

surface area = bh + L(s1+s2+s3)

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8 0
2 years ago
3(x 2) 11 is greater than 20
Allushta [10]
3(x+2)+11>20
minus 11 both sides
3(x+2)>9
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4 0
2 years ago
Given a circle with radius of 2, which is the degree measure of an arc whose length is 1/2 ?
Finger [1]
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3 0
3 years ago
Given the function f(x) = 2x+4 and the domain: {-1,0,1},determine the range
Svetlanka [38]

Answer:

f(x) = 2x + 4 domains {-1, 0, 1}

range {2, 4, 6}

(please mark brain if this helps and is correct)

Step-by-step explanation:

to solve f(x) to find the range you would want to input all the domain numbers in the equation f(x) to get the range of all the numbers you need

step 1: take the first domain number and input it into your equation where x is

ex: 2x + 4   [2(-1) + 4] = -2 + 4 = 2

step 2: add the second domain number and input it into your equation where x is

ex: 2x + 4   [2(0) + 4] = 0 + 4 = 4

step 3: add the last domain number and input it into your equation where x is

ex: 2x + 4   [2(1) + 4] = 2 + 4 = 6

Now we have determined what the range is

6 0
2 years ago
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