Answer:
1. When the number of calories a person consumes is equal to the number of calories he or she burns in a day, that person's body is in Energy Balance.
2. Someone who is in Positive Energy Balance eats more calories in a day than he or she bums.
3. Negative Energy Balance occurs when the number of calories a person bums in a day is greater than the amount he or she consumes.
4. Weight management involves applying strategies that allow someone to keep his or her body weight within a healthy.
5. The Basal metabolic rate is the amount of energy uses in order to perform its basic physiological functions.
6. The Thermic effect of food refers to the number of calories burned in order to digest absorb, metabolze, and store food.
7. The Lean body mass refers to his or her total body - fat mass.
Explanation:
This group of statements are related to body weight, the balance between the energy we consume through food and all the energy we burn through excercise and different activities, such as only mantaining our body temperature and normal processes.
Answer:
The client traction weights are resting on the floor.
Explanation:
The immediate action of the nurse should be to reapply the weights to give traction to the fracture. The health care provider must be notified that the weights were lying on the floor, and the client should be realigned in bed. The client's blood pressure is slightly elevated; this could be related to pain and muscle spasms resulting from lack of pressure to reduce the fracture. Oozing of clear fluid is normal, as is the capillary refill time.
DIF: Applying/Application REF: 1060 KEY: Fracture| traction
MSC: Integrated Process: Communication and Documentation
NOT: Client Needs Category: Safe and Effective Care Environment: Management of Care
Answer:
Membrane bound cell organelles
Explanation:
A prokaryotic cell lacks a membrane defined nucleus and all the membrane-bound organelles. A eukaryotic cell has a membrane-bound nucleus and other membrane-bound organelles such as mitochondria, chloroplasts, endoplasmic reticulum, lysosomes, Golgi apparatus, etc.
To determine if a cell is a prokaryotic or eukaryotic, one can look for the nucleus and the membrane-bound organelles. If the cell has a nucleus and membrane-bound organelles, it is a eukaryotic cell. The absence of these structures makes it a prokaryotic cell.
Answer:
True, polar covalent bond
Explanation:
A covalent bond is one of the types of the chemical bond which is formed when the electrons are shared between the two atoms.
Based on the magnitude of the sharing of electrons between atoms two types of covalent bonds are formed which are: pure covalent bond in which the electrons are shared equally whereas the polar covalent bond in which the electrons are shared unequally between two atoms.
Since there is a type of covalent bond formed which has unequal sharing of electrons called polar covalent bond therefore true is the correct answer.
Answer:
C. The green allele is recessive to the yellow allele
Explanation:
Complete dominance occurs when one gene variant or allele referred to as the 'dominant allele' completely masks the expression of another allele referred to as the 'recessive allele' in heterozygous individuals, i.e., in individuals carrying one copy of the dominant allele and one copy of the recessive allele for a particular locus/gene (whereas homo-zygous individuals carry the same alleles for a given locus/gene). Mendel crossed pure lines of pea plants, i.e., homo-zygous lines for different traits such as seed color (yellow and green) and seed shape (round and wrinkled). In this case, the parental cross was YY x yy, where the 'Y' allele is dominant and encodes for yellow seed color, and the 'y' allele is recessive and encodes for green seed color. From this cross, Mendel obtained a hybrid F1 (i.e., all progeny was heterozygous with genotype Yy). An expected 3:1 ratio as observed in this case (6,022 yellow and 2,001 green seed >> 3:1 ratio) is characteristic of the progeny that results from mating between F1 heterozygous parents, where each parent has one dominant allele and one recessive allele, i.e., F1 parental cross: Yy x Yy >> F2: 1/4 YY (yellow color); 1/2 Yy (yellow color); 1/4 (green color) >> 3:1 ratio of yellow to green seeds.
