Question

Compare the perimeter and area of the original figure to the perimeter and area of the reduced figure using the scale factor. A smaller rectangle has a length of 3 and width of 1. A larger rectangle has a length of 6 and width of 2. Which statements are true about the comparison between the two figures? Check all that apply. The scale factor is 2. The scale factor is One-half The perimeter of the model is the product of the scale factor and the perimeter of the original rectangle. The area of the reduced figure is half the area of the original figure. The area of the reduced figure is (One-half) squared, one-fourth times the area of the original figure.

Answer 1

Answer:

Statement 2: The scale factor is One-half

Statement 3: The perimeter of the model is the product of the scale factor and the perimeter of the original rectangle.

Statement 5: The area of the reduced figure is (One-half) squared, one-fourth times the area of the original figure.

Step-by-step explanation:

A smaller rectangle has a length of 3 and width of 1

Perimeter: 2(3+1) = 8

Area: 3×1 = 3

A larger rectangle has a length of 6 and width of 2

Perimeter = 2(6+2) = 16

Area = 6×2 = 12

Comparing areas:

Smaller : larger

3 : 12

1 : 4

Comparing perimeters:

Smaller : larger

8 : 16

1 : 2

Answer 2

Answer:

- The scale factor is one-half

- The perimeter of the model is the product of the scale factor and the perimeter of the original rectangle

-The area of the reduced figure is (1/2)^2 = 1/4 times the area of the original figure

Step-by-step explanation:

The ratio of the length of the original rectangle to that of the reduced rectangle is 6 to 3, or a factor of 1/2. The ratio of the width of the original rectangle to that of the reduced rectangle is 2 to 1, or, again, a factor of 1/2. So, because this ratio of 1/2 is constant, we know the total scale factor is 1/2, making B correct.

The perimeter of a rectangle is: $P=2l+2w$, where l is the length and w is the width. The perimeter of the reduced figure is: P = 2 * 3 + 2 * 1 = 6 + 2 = 8 units. The perimeter of the original figure is: P = 2 * 6 + 2 * 2 = 12 + 4 = 16 units.

Notice that 16 * (1/2) = 8, which means that the perimeter of the scale-factored, reduced rectangle is "the product of the scale factor (which is 1/2) and the perimeter of the original rectangle (which is 16)". So, C is correct.

The area of a rectangle is: $A=lw$, where l is the length and w is the width. The area of the reduced figure is: A = 3 * 1 = 3 units squared. The area of the original figure is: A = 6 * 2 = 12 units squared.

Notice that 12 * (1/4) = 3, which means that E is correct, but D is wrong.

Hope this helps!