If a tables patterns is that the f(x) values are being divided by four, what is the common ratio

There are 3 types of sweets in a jar.

KengaRu [80]

Answer:

$\frac{2}{3}$

Step-by-step explanation:

Given:

Number of eclairs = 3

Number of humbugs = $2x + 6=2(x+3)$

Number of mints = $x$

Therefore, total number of sweets in the jar is,

$S=3+2x+6+x=3x+9=3(x+3)$

Now, probability of selecting a sweet to be humbug is given as:

$P(humbug)=\frac{\textrm{number of humbugs}}{\textrm{number of sweets}}\\P(humbug)=\frac{2(x+3)}{3(x+3)}=\frac{2}{3}$

Therefore, the probability that it is a humbug is $\frac{2}{3}$ .

7 0

3 years ago

If the m∠SRW = 85°, what are the measures of ∠VRU and ∠URW?<br><br> m∠VRU = °<br><br> m∠URW = °

alina1380 [7]

Answer:

see explanation

Step-by-step explanation:

∠TRV = ∠SRW ( vertical angles ), hence

2x + 15 = 85 ( subtract 15 from both sides )

2x = 70 ( divide both sides by 2 )

x = 35

Hence

∠VRU = 2x + 10 = ( 2 × 35) + 10 = 70 + 10 = 80°

and

∠URW + ∠VRU + ∠SRW = 180 ( sum of angles in a straight line ), thus

∠URW + 80 + 85 = 180

∠URW + 165 = 180 ( subtract 165 from both sides )

∠URW = 15°

5 0

3 years ago

Read 2 more answers

Rey feeds his dog 2/5 of a can of dog food in the morning and 4/5 of a can in the evening. How many cans of dog food will Rey ne

QveST [7]

Answer:

6 cans total if im correct

6 0

3 years ago

9x^2+6x-8 factor trinomia

Yanka [14]

(3x-2)(3x+4) yayyyyy

4 0

3 years ago

Read 2 more answers

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

podryga [215]

Answer:

(a) $0.408m/sec^2$

(b) $0.134m/sec^2$

(c) $0.039m/sec^2$

Step-by-step explanation:

We have given velocity as function of t $v(t)=\frac{85t}{(8t+14)}$

Acceleration is equation rate if change of velocity with respect to time

So $a=\frac{dv}{dt}=\frac{(8t+14)85-85t\times 8}{(8t+14)^2}$

(a) Acceleration at t = 5 sec

$a=\frac{(8\times 5+14)85-85\times 5\times 8}{(8\times 5+14)^2}=0.408m/sec^2$

(b) Acceleration at t = 10 sec

$a=\frac{(8\times 10+14)85-85\times 10\times 8}{(8\times 10+14)^2}=0.134m/sec^2$

(c) Acceleration at t = 20 sec

$a=\frac{(8\times 20+14)85-85\times 20\times 8}{(8\times 20+14)^2}=0.039m/sec^2$

5 0

3 years ago