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Anna71 [15]
3 years ago
15

If the ordered pairs graphed are all equivalent ratios

Mathematics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

huh?

Step-by-step explanation:

whats the question

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The solution of the equation 7x+2=23 is ?
ikadub [295]
7x+2=23
Move 2 to the other side
7x=23-2
7x=21 

To isolate the x divide both sides by 7
x=3 

To check plug the value of x back in 

7(3)+2=23
21+2=23
23=23
3 0
3 years ago
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Suppose U = {1, 2, 3, 4, 5, 6, 7, 8} is the universal set, and P= {1, 3, 5, 7}. what is P'
katen-ka-za [31]

Answer:

P'= {2, 4, 6 ,8}

Step-by-step explanation:

If you mean by P' - ''complement of P'' or ''U\P'' or ''all elements that does not belong to the P '' or  ''¬P'' ( which is all the same) then correct answer is

P'= {2, 4, 6 ,8}.

Good luck!!!


8 0
3 years ago
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What Is 3,552,308,725 In Word Form
Liono4ka [1.6K]
3, 552, 308, 725 in word form is:

Three billion, five hundred fifty-two million, three hundred eight thousand, seven hundred twenty-five.

7 0
3 years ago
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41 kilometers to meter
g100num [7]

Answer:

41000 meters

Step-by-step explanation:

multiply the length value by 1000

4 0
3 years ago
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|1/2b-8|=|1/4b-1|<br> b=____ and ____
Deffense [45]

Answer:

  b = 12 and 28

Step-by-step explanation:

The absolute value equation |1/2b-8| = |1/4b-1| resolves to a piecewise linear function with three pieces. There are two solutions.

<h3>Domains</h3>

The absolute value function on the left has a turning point where its value is zero:

  1/2b -8 = 0

  b -16 = 0

  b = 16

The absolute value function on the right has a turning point where its value is zero:

  1/4b -1 = 0

  b -4 = 0

  b = 4

For b > 16, both absolute value functions are identity functions. In this domain, the equation is ...

  1/2b -8 = 1/4b -1

For 4 < b < 16, the function on the left negates its argument, so the equation in this domain is ...

  -(1/2b -8) = 1/4b -1

For b < 4, both functions negate their arguments, so the equation in this domain is ...

  -(1/2b -8) = -(1/4b -1)

For the purpose of finding the value of b, this is effectively identical to the equation for b > 16. (The value of b does not change if we multiply both sides of the equation by -1.)

<h3>Solutions</h3>

<u>Domain b < 4 ∪ 16 < b</u>

  1/2b -8 = 1/4b -1

  2b -32 = b -4 . . . . . . . . multiply by 4

  b = 28 . . . . . . . . . . . . add 32-b to both sides

This solution is in the domain of the equation, so is one of the solutions to the original equation.

<u>Domain 4 < b < 16</u>

  -(1/2b -8) = 1/4b -1 . . . . equation in this domain

  -2b +32 = b -4 . . . . . . multiply by 4

  36 = 3b . . . . . . . . . . . add 2b+4 to both sides

  12 = b . . . . . . . . . . . . divide by 3

This solution is in the domain of the equation, so is the other solution to the original equation.

<h3>Graph</h3>

For the purposes of the graph, we have define the function g(b) to be the difference of the two absolute value functions. The solutions are found where g(x) = 0, the x-intercepts. The graph shows those to be ...

  b = 12  and  b = 28

__

<em>Additional comment</em>

Defining g(b) = |1/2b-8| -|1/4b-1|, we can rewrite it as ...

  g(b)=\begin{cases}7-\dfrac{1}{4}b&\text{for }b < 4\\-\dfrac{3}{4}b+9&\text{for }4\le b < 16\\\dfrac{1}{4}b-7&\text{for }16\le b\end{cases}

Then the solutions are the values of b that make g(b) = 0.

4 0
2 years ago
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