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Dafna1 [17]
3 years ago
10

Add. (−5x4+6x2−43)+(6x4−x2+12x+12) Express the answer in standard form. Enter your answer in the box.

Mathematics
2 answers:
Elan Coil [88]3 years ago
4 0

Answer:

x^2+12x-15

Step-by-step explanation:

julia-pushkina [17]3 years ago
3 0

Answer:

Step-by-step explanation:

(-5x4+6x2-43)+(6x4-x2+12x+12)

(x4+5x2+12x-31)

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Jose received $250 for his birthday from his family. He wishes to buy a motorcycle and decides to use his birthday money towards
BartSMP [9]

Answer:

He will have $276.10 available towards the down payment for his motorcycle

Step-by-step explanation:

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

In this problem, we have that:

P = 250, t = 2, r = 0.05

Compounded quarterly, so n = 12/4 = 3.

We have to find A.

A = P(1 + \frac{r}{n})^{nt}

A = 250(1 + \frac{0.05}{3})^{3*2}

A = 276.1

He will have $276.10 available towards the down payment for his motorcycle

8 0
3 years ago
A circle has a radius of 6 cm. How can I find the diameter of the same circle?
Sedbober [7]
Multiply 6 by 2 and add 6cm. the radius is half of the diameter so just multiply by two and add the number.
6 0
3 years ago
Can I get help please ​
aleksandrvk [35]

Answer:

x > -3.2

Step-by-step explanation:

6 0
3 years ago
Hey! Can someone help me with this! Please thank u!
NeTakaya

Step-by-step explanation:

1. vertical opposite angles

2. corresponding angles

3. alternate interior angles

4. alternate exterior angles

5. corresponding angles

6. vertical opposite angles

7. alternate exterior angles

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7 0
3 years ago
-3+9x>87 or -x-9>-17​
Alex_Xolod [135]

Answer:

\large\boxed{x\in(-\infty,\ 8)\ \cup\ (10,\ \infty)}

Step-by-step explanation:

-3+9x>87\qquad\text{add 3 to both sides}\\\\9x>90\qquad\text{divide both sides by 9}\\\\\boxed{x>10}\to(1)\\\\-x-9>-17\qquad\text{add 9 to both sides}\\\\-x>-8\qquad\text{change the signs}\\\\\boxed{x10\ or\ x

7 0
3 years ago
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