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3 years ago

11

If 40 grams of NH3 are dissolved in 100 mL of water at 10 degrees Celsius, how many more grams of NH3 would I need to add to mak

e this a saturated solution?
Which one is it?

25 g

30 g

20 g

0 g

1 answer:

Katen [24]3 years ago

6 0

20 g is the answer to make it a saturated solution

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Extend your thinking: Why do you think the temperature does not change much during a phase change? If possible, discuss your ans

stiv31 [10]

Answer:

The rate of temperature change does not stay constant and decreases over time because the temperature difference decreases over time.

Explanation:

The temperature difference is due to Thermal Equilibrium

4 0

3 years ago

What is the molarity of a solution made from 325.4 g of AlCl3 (MM 133.34 g/mol) to make 500.0 mL?

NISA [10]

Answer : The molarity of a solution is, 4.88 M

Explanation : Given,

Mass of $AlCl_3$ = 325.4 g

Volume of solution = 500.0 mL

Molar mass of $AlCl_3$ = 133.34 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }AlCl_3\times 1000}{\text{Molar mass of }AlCl_3\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{325.4g\times 1000}{133.34g/mole\times 500.0mL}=4.88mole/L=4.88M$

Therefore, the molarity of a solution is, 4.88 M

6 0

3 years ago

Read 2 more answers

Using complete sentences, explain how to predict the products and balance the reaction between sulfuric acid and potassium hydro

My name is Ann [436]

Answer:

The answer to your question is given below.

Explanation:

The reaction of sulfuric acid and potassium hydroxide is called neutralisation.

Neutralisation is a reaction involving an acid and a base which produces salt and water only.

For the react between sulfuric acid, H2SO4 and potassium hydroxide, KOH, we can predict the products obtained as follow:

H2SO4 + KOH —>

In solution, H2SO4 and KOH will dissociate as follow:

H2SO4(aq) —> 2H^+(aq) + SO4^2-(aq)

KOH(aq) —> K^+(aq) + OH^-(aq)

H2SO4 + KOH —>

2H^+(aq) + SO4^2-(aq) + K^+(aq) + OH^-(aq) —> K^+(aq) + SO4^2-(aq) + 2H^+(aq) + OH^-

H2SO4 + KOH —> K2SO4 + H2O

Now, we can balance the above equation as follow:

H2SO4 + KOH —> K2SO4 + H2O

There are 2 atoms K on right side and 1 atom on the left side. It can be balance by writing 2 in front of ko as shown below:

H2SO4 + 2KOH —> K2SO4 + H2O

There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by writing 2 in front of H2O as shown below:

H2SO4 + 2KOH —> K2SO4 + 2H2O

Now,the equation is balanced.

6 0

4 years ago

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu

Pani-rosa [81]

83.3 mL

Explanation:

M $_{i}$ = 3M

V $_{i}$ = 50mL

M $_{f}$ = 1.80M

Unknown:

V $_{f}$ = ?

Solution:

To solve this problem we must understand that the initial and final number of moles remains the same.

Number of moles = molarity x volume

Molarity x volume of initial solution = Molarity x volume of final solution

Therefore:

M $_{i}$ x V $_{i}$ = M $_{f}$ x V $_{f}$

M is the molarity

V is the volume

i = initial state

f = final state

input the parameters;

3 x 50 = 1.8 x V $_{f}$

V $_{f}$ = 83.3 mL

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

8 0

3 years ago

Read 2 more answers

What is 7.008 x 10^6 in standard form?

elena-14-01-66 [18.8K]

Answer:10

6

=

1000000

or a 1 with 6 zeroes.

Explanation:So

5

⋅

10

6

=

5000000

or five million.

7 0

4 years ago