3 years ago

Find values of the shape

Mathematics

1 answer:

slava [35]3 years ago

3 0

Answer: Sorry mate it didn't pop up anyway hi man how's it been

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The graph of (6-4x)^2/2x^2-5x+12 has a horizontal asymptote at y =

vova2212 [387]

Answer:

$y = 8$

Step-by-step explanation:

The given rational function is

$y = \frac{ {(6 - x)}^{2} }{ {2x}^{2} - 5x + 12 }$

Let us expand the numerator to get;

$y = \frac{(6 - 4x)(6 - 4x)}{2 {x}^{2} - 5x + 12 }$

$y = \frac{36 - 48x + 16 {x}^{2} }{2 {x}^{2} - 5x + 12 }$

We can observe that, the degree of the numerator is the same as the degree of the denominator.

Therefore the horizontal asymptote is the ratio of the coefficient of the leading terms:

$y = \frac{16}{2}$

The horizontal asymptote is

$y = 8$

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Can someone answer this please. I will mark brainliest, answer and provide explanation please.

LekaFEV [45]

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4. determine whether the relation is a function(

mixas84 [53]

Answer:

No, bacause each X (first value), need to have just once Y value (second one). Here you have two values for 3 (4 and 4)

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19. In the expression: 5.3t + (12-3) - 7 + 6.2,

Marat540 [252]

Answer:

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What is 2 1/4 x 3 1/2

Usimov [2.4K]

9.625 in decimals hope this helps

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