Starting with acetylene and bromoethane, show how you would use reagents from the table to synthesize 3-hexanone.

Chemistry

1 answer:

Jobisdone [24]3 years ago

3 0

solution:

A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg

Starting by hitting acetylene with NaNH2 to deprotonate, this C-- will attack the C connected to the Br Sn2 style to lengthen the chain by two carbons.

Do this same thing again with the other CH of the acetylene and another bromoethaneto get a six carbon chain, namely, 3-hexyne.

Now, reduce the alkyne to an alkene via H2/Pd/C, and that gives 3-hexene.

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