Answer:
A) g = 9.751 m/s², B) h = 2.573 10⁴ m
Explanation:
The angular velocity of a pendulum is
w = √ g / L
Angular velocity and frequency are related.
w = 2π f
f = 1 / 2π √ g / L
A) with the initial data we can look for the pendulum length
L = 1 /4π² g / f²
L = 1 /4π² 9,800 / 0.3204²
L = 2.4181 m
The length of the pendulum does not change, let's look for the value of g for the new location
g = 4π² f² L
g = 4π² 0.3196² 2.4181
g = 9.75096 m / s²
g = 9.751 m/s²
B) The value of the acceleration of gravity can be found with the law of universal gravitation
F = G m M /
²
And Newton's second law
W = m g
W = F
G m M /
² = mg
g = G M /
²
² = G M / g
Let's calculate
² = 6.67 10⁻¹¹ 5.98 10²⁴ /9.75096
R = √ 4.0905 10¹³ = √ 40.9053 10¹²
R = 6.395726 10⁶ m
The height above sea level is
h = R - [tex]R_{e}[/tex
h = (6.395726 -6.37) 10⁶
h = 0.0257256 106
h = 2.573 10⁴ m
Answer:
Current = 3 Amperes
Explanation:
Given the following data;
Quantity of charge = 6 C
Time = 2 seconds
To find how many amps are moving through this wire;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
6 = current * 2
Current = 6/2
Current = 3 Amperes
Answer:
W_apparent = 93.1 kg
Explanation:
The apparent weight of a body is the weight due to the gravitational attraction minus the thrust due to the fluid where it will be found.
W_apparent = W - B
The push is given by the expression of Archimeas
B = ρ_fluide g V
ρ_al = m / V
m = ρ_al V
we substitute
W_apparent = ρ_al V g - ρ_fluide g V
W_apparent = g V (ρ_al - ρ_fluide)
we calculate
W_apparent = 980 50 (2.7 - 0.8)
W_apparent = 93100 g
W_apparent = 93.1 kg