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mr Goodwill [35]
3 years ago
6

The underlying part is the place value what is it

Mathematics
1 answer:
nignag [31]3 years ago
4 0
The 0 is in the thousands place.
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What is the algebraic expressions of 8-6k​
Komok [63]
Eight decreased by six times the number k

The difference of eight and the product of six and the number k

Eight minus six times k

Six multiplied to k is less than 8
4 0
3 years ago
What is the unit rate<br> $140 for 18ft
scZoUnD [109]
You have an equation:18ft=$140. To find the unit rate for ft, divide both by 18:/18ft= $140/18= $7.78/1ft.
8 0
3 years ago
Simplify
Diano4ka-milaya [45]

Answer:

\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}

Step-by-step explanation:

16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}

=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}

5 0
3 years ago
Solve for y.<br> 6 y<br> 36 3<br> y=Blank 1<br> Blank 1<br> Add your answer
Gemiola [76]

Answer: 60.5

Step-by-step explanation:

Since you’re solving for y, you want to get it by itself to get a clean reading answer of y= blank.

So in 6y=363 you would want get rid of that 6 from the y, do you would divide both sides by 6.

6y/6 = 363/6

And then you’d get

y=60.5 once you finish dividing.

5 0
3 years ago
Can someone help me with this problem?<br> -20v2 + 12v2
baherus [9]

Answer:

-8v2

Step-by-step explanation:

6 0
3 years ago
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