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BARSIC [14]
2 years ago
7

If you apply the changes below to the quadratic parent function, f(x) = x2, what is the equation of the

Mathematics
1 answer:
Vesnalui [34]2 years ago
7 0

Answer:

C. g(x) + (-3x + 1)2

Step-by-step explanation:

did the test for it

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A customer goes to a bank and gets change for a $100 bill. The change is to be in $1, $5, and $10 bills. There were four times a
alexira [117]

Answer:

12

Step-by-step explanation:

x = number of $1 bills

y = number of $5 bills

z = number of $10 bills

We know that:

x + y + z = 25 (total amount of bills)

x + 5y + 10z = 100 (total amount of money)

y = 4z (Given)

Substitute the third equation into the first one.

x + 4z + z = 25

x = 25 - 5z

Put this into the second equation.

(25 - 5z) + 5 (4z) + 10z = 100

Simplify and solve.

25 - 5z + 20z + 10z = 100

25z + 25 = 100

25z = 75

z = 3

Substitute this into y = 4z

y = 4 * 3

y = 12

So, there are 12 $5 bills.

5 0
2 years ago
Read 2 more answers
zoe wrote 3/5 of her essay in 30 minutes. assuming she wrote the paper at a constant rate the entire time, which expression can
vodomira [7]
3/5 in 30 mins, 5*30=150, then she would write 3/150 or 1/50 each minute
6 0
3 years ago
Read 2 more answers
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
I WILL MARK BRAINIEST<br> I got one correct there should be about one more that’s also right
Lesechka [4]

So essentially an adjacent angle is when two angles have a common side and a common vertex.

So knowing that we can determine from the picture all the adjacent angles:

D) <2 and <3 are adjacent angles

E) <1 and <3 are adjacent angles

F) <1 and <5 are adjacent angles

I hope this helps.

7 0
3 years ago
What is the factorization of 36z+60
Zolol [24]

Answer:

<u>12 ( 3z + 5 )</u>

Step-by-step explanation:

6 0
2 years ago
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