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MrRa [10]
3 years ago
10

the area of John's garden is the same size of Sarah's garden. John's garden has a width of 9 meters, and Sarah's garden has a wi

dth of 6 meters. The length of Sarah's garden is 2 meters more than John's. What is the combined area of both garden's?
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

The combined area of both gardens is 72 square meters.

Step-by-step explanation:

Given,

Width of John's garden = 9 meters

Width of Sarah's garden = 6 meters

Let,

l be the length of John's garden.

Length of John's garden = l+2

It is given that area of both gardens is same,

Area of Sarah's garden = Area of John's garden

Length * Width = Length * Width

6*(l+2)=9*l\\6l+12=9l\\12=9l-6l\\12=3l\\3l=12

Dividing both sides by 3

\frac{3l}{3}=\frac{12}{3}\\l=4

Length of John's garden = 4 meters

Length of Sarah's garden = 4+2 = 6 meters

Combined area = Area of John's + Area of Sarah's

Combined area = (Length * Width) + (Length * Width)

Combined area = (4*9)+(6*6)

Combines area = 36+36 = 72 square meters

The combined area of both gardens is 72 square meters.

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7 0
3 years ago
Sydney purchases a new car for $27,500. The value of the car decreases at rate of 15% each year. In approximately will the $1,25
Pani-rosa [81]

Answer:

Time taken n = 19 years (Approx)

Step-by-step explanation:

Given:

Amount of car P = $27,500

Decrease rate r = 15% = 0.15

Final amount A = $1,254

Find:

Time taken n

Computation:

A = P[1-r]ⁿ

1,254 = 27,500[1-0.15]ⁿ

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Time taken n = 19 years (Approx)

8 0
2 years ago
Read 2 more answers
The top and bottom margins of a poster 66 cm each, and the side margins are 44 cm each. If the area of the printed material on t
jasenka [17]

Answer:

  • width: 24 cm
  • height: 36 cm

Step-by-step explanation:

When margins are involved, the smallest area will be the one that has its dimensions in the same proportion as the margins. If x is the "multiplier", the dimensions of the printed area are ...

  (4x)(6x) = 384 cm^2

  x^2 = 16 cm^2 . . . . . divide by 24

  x = 4 cm

The printed area is 4x by 6x, so is 16 cm by 24 cm. With the margins added, the smallest poster will be ...

  24 cm by 36 cm

_____

<em>Comment on margins</em>

It should be obvious that if both side margins are 4 cm, then the width of the poster is 8 cm more than the printed width. Similarly, the 6 cm top and bottom margins make the height of the poster 12 cm more than the height of the printed area.

_____

<em>Alternate solution</em>

Let w represent the width of the printed area. Then the printed height is 384/w, and the total poster area is ...

  A = (w+8)(384/w +12) = 384 +12w +3072/w +96

Differentiating with respect to w gives ...

  A' = 12 -3072/w^2

Setting this to zero and solving for w gives ...

  w = √(3072/12) = 16 . . . . matches above solution.

__

<em>Generic solution</em>

If we let s and t represent the side and top margins, and we use "a" for the printed area, then the above equation becomes the symbolic equation ...

  A = (w +s)(a/w +t)

  A' = t - sa/w^2

For A' = 0, ...

  w = √(sa/t)

and the height is ...

  a/w = a/√(sa/t) = √(ta/s)

Then the ratio of width to height is ...

  w/(a/w) = w^2/a = (sa/t)/a

  width/height = s/t . . . . . . the premise we started with, above

6 0
3 years ago
95% of the students passed the math final exam. If 200 students take the final, how many students passed? Steps greatly apprecia
Anit [1.1K]

Answer:

190 students

Step-by-step explanation:

Set up a proportion:

95/100 = x/200

Cross multiply:

100x = 19000

Simplify:

x = 190 students

3 0
3 years ago
3
siniylev [52]

Answer:

179

Step-by-step explanation:

The total number of animals in the river was 632.

A herd of 187 elephants and 266 zebras left the river area.

Adding them up, the total number of animals that left the river area is:

187 + 266 = 453

Therefore, the total number of animals left at the river area is the subtraction for the animals that left the river area from the number of animals that were there initially:

632 - 453 = 179

3 0
3 years ago
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