1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leona [35]
2 years ago
6

A student predicts that a solution of ethanol (C2H5OH) and water will have a lower density at room temperature than that of pure

water. Which tools would most help the student test this prediction?
Will give brainly
Chemistry
2 answers:
ohaa [14]2 years ago
4 0

Answer:

It would probably be, something that can take up moisture to test it.

Explanation:

(to see if it can evaporate)

Lubov Fominskaja [6]2 years ago
3 0
It could probably be something that could take moisture to test it
You might be interested in
Electrical conductivity is an example of what property
Anika [276]
<span>melting point-electrical conductivity-color-<span>density
please mark as brainliest

</span></span>
3 0
3 years ago
Read 2 more answers
Can you Guys please help me on 14,and 15
jok3333 [9.3K]
14. is a and i think 15. is b
7 0
2 years ago
Read 2 more answers
​What is the concentration of the solution prepared by dissolving 2.35 g of KBr (M = 119 g/mol) in 250 mL of water? 
dusya [7]

Answer:

The concentration of KBr is  C = 0.07899 \ mol   L^{-1}

Explanation:

From the question we are told that

      The mass of KBr is  m_{KBr}  = 2.35 \ g

       The molar mass of KBr is  M_{KBr} =  119 g/mol

       Volume of water is V = 250 \ mL = 250 *10^{-3} =  0.250 \ L

This implies that the volume of  the solution is  V = 250 mL

The number of moles of KBr is

         n = \frac{m_{KBr}}{M_{KBr}}

Substituting values

         n =  \frac{2.35}{119}

        n = 0.01975 \ mol

The concentration of KBr is mathematically represented as

                C = \frac{0.01975}{0.250}

                C = 0.07899 \ mol   L^{-1}

3 0
3 years ago
A stock solution of HNO3 is prepared and found to contain 13.5 M of HNO3. If 25.0 mL of the stock solution is diluted to a final
salantis [7]

Answer : The correct option is, (C) 0.675 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = concentration of HNO_3 = 13.5 M

M_2 = concentration of diluted solution = ?

V_1 = volume of HNO_3 = 25.0 ml  = 0.0250 L

conversion used : (1 L = 1000 mL)

V_2 = volume of diluted solution = 0.500 L

Now put all the given values in the above law, we get the concentration of the diluted solution.

13.5M\times 0.0250L=M_2\times 0.500L

M_2=0.675M

Therefore, the concentration of the diluted solution is 0.675 M

8 0
3 years ago
If your end product is 1.5 moles of KMnO 4 how many moles of manganese oxide were used in the reaction? The equation for the pro
vovikov84 [41]

Answer:

1.5 moles

Explanation:

The equation of the reaction is given as:

2 MnO2 + 4 KOH + O2 --> 2KMnO 4 + 2KOH + H2

From the equation,

2 moles of MnO2 produces 2 moles of KMnO4

x moles of MnO2 would produce 1.5 moles of KMnO4

2 = 2

x = 1.5

Solving for x;

x = 1.5 * 2 / 2

x = 1.5 moles

4 0
2 years ago
Other questions:
  • Which process occurs in all living organisms at all times?
    15·1 answer
  • What are the advantages of adulteration​
    5·1 answer
  • How did the gold foil experiment lead to the discovery of the nucleus?
    10·1 answer
  • Isotopes of an element will {always, sometimes, or never) have the same number of protons.
    7·1 answer
  • What properties do metalloids have?
    6·1 answer
  • Which information is sufficient to differentiate a
    7·2 answers
  • PLEASE HELP
    15·1 answer
  • Which of the following statement explains how fossils can be useful?
    6·1 answer
  • Describe un modelo matemático para representar lo que sucede en cada una de las reacciones químicas  (incluye toda la simbología
    7·1 answer
  • No links please answer correctly. A board measurements 213 inches. How many feet is this?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!