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I am Lyosha [343]
4 years ago
15

How does a buffer resist change in ph upon addition of a strong acid?

Chemistry
1 answer:
lora16 [44]4 years ago
8 0
Any buffer exists in this equilibrium
 
  HA <=> H^+ + A^-
In a buffer, there is a large reservoir of both the undissociated acid (HA) and its conjugate base (A^-) 

When a strong acid is added, it reacts with the large reservoir of the conjugate base (A^-) forming a salt and water. Since this large reservoir of the conjugate base is used, the ph does not alter drastically, but instead resist the pH change. 

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Answer:

92.06 g/mol

Explanation:

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that temperature is saturated.

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Drag each label to the correct location on the equation. Each label may be used more than once.
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8 0
2 years ago
What is the volume of 1,000 kg of ice? Please explain.
mars1129 [50]

Answer:

Volume of ice is 1.09 m³.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass of ice = 1000 Kg

Volume = ?

Solution:

The density of ice is 919 Kg/m³

d = m/v

v = m/d

v = 1000 Kg / 919 Kg/m³

v = 1.09 m³

6 0
3 years ago
You need a 35% alcohol solution. on hand, you have a 405 ml of a 30% alcohol mixture. you also have 80% alcohol mixture. how muc
Bumek [7]

You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.

You can use a modified dilution formula to calculate the volume of 80 % alcohol

V1×C1 + V2×C2 = V3×C3

Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL

(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc

80x + 12 150 = 14 175 + 35 x

45x = 2025

x = 2025/45 = 45

4 0
3 years ago
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