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I am Lyosha [343]
3 years ago
15

How does a buffer resist change in ph upon addition of a strong acid?

Chemistry
1 answer:
lora16 [44]3 years ago
8 0
Any buffer exists in this equilibrium
 
  HA <=> H^+ + A^-
In a buffer, there is a large reservoir of both the undissociated acid (HA) and its conjugate base (A^-) 

When a strong acid is added, it reacts with the large reservoir of the conjugate base (A^-) forming a salt and water. Since this large reservoir of the conjugate base is used, the ph does not alter drastically, but instead resist the pH change. 

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Ethanol had a boiling point of 78.4°C. Propane has a boiling point of -42°C. Suggest why.​
Gwar [14]

Answer:

Chemical compounds all have different melting points.

Explanation:

chemical compounds all have different freezing and boiling points. Different chemical compounds means they will have different chemical structures.

7 0
3 years ago
1. What is oxidation? * O a. it is loss of electrons O b. it is gain of electrons O c. it is loss of protons O d. none of the ab
Lemur [1.5K]

Answer:

yes

Explanation:

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7 0
3 years ago
The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘c is 2000 m/s. Note that 1. 0 mol of diatomic hydrogen at
Leno4ka [110]

The rms speed will be 500 m/s

<h3>What is Root mean square speed ?</h3>

Root mean square speed (Vrms) is defined as the square root of the mean of the square of speeds of all molecules.

Root mean square speed (vrms) Root mean square speed (vrms) is defined as the square root of the mean of the square of speeds of all molecules

It is given that

Speed of a diatomic hydrogen molecule,2000 m/s

Mol of diatomic hydrogen,1.0

Temperature,50°C

The rms speed of diatomic molecule will be:

√(3KT)/( m)

The translational kinetic energy of a gas molecule is given as:

K.E = (3/2)KT

K.E = (1/2) mv²

where,

v = root mean square velocity

m = mass of one mole of a gas

(3/2)KT = (1/2) mv²

v = √(3KT)/m  

FOR H₂:  v = √(3KT)/m = 2000 m/s  

Here,

mass of 1 mole of oxygen = 16 m

velocity of oxygen = √(3KT)/(16 m)

velocity of oxygen = (1/4) √(3KT)/m

velocity of oxygen = (1/4)(2000 m/s) = 500 m/s

Therefore the  rms (root-mean-square) speed of a oxygen molecule at 50∘c is 500m/s.

To know more about Root mean square speed

brainly.com/question/7213287

#SPJ4

3 0
2 years ago
Add them to your friend's list and have them support you along your Brainly journey. Just go to the profile of the person you’d
Makovka662 [10]

Answer:

yup that's how you make friends with people on brainly

8 0
2 years ago
5)
Drupady [299]

What amount of heat absorbs 50 g of steel (ce = 0.115 cal / g. ° C) that

does its temperature vary by 25 ° C?

Answer:

143.75cal

Explanation:

Given parameters:

Mass of steel  = 50g

Specific heat capacity of the steel  = 0.115cal/g°C

Temperature  = 25°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat to cause this temperature change is dependent on mass and specific heat capacity of the substance.

  Amount of heat  = m C (ΔT)

m is the mass

c is the specific heat capacity

ΔT is the temperature change

 Now insert the parameters and solve;

  Amount of heat  = 50 x 0.115 x 25

  Amount of heat  = 143.75cal

4 0
2 years ago
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