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Sati [7]
3 years ago
8

5.0 liters of a 0.1 M Ca(OH), solution

Chemistry
1 answer:
LiRa [457]3 years ago
3 0

Answer:

0.5mol

Explanation:

mole = concentration × volume

mole = 0.1 × 5.0 = 0.5mol

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There are on average 43 g of sugar and 355 mL can of soda please calculate the molarity of sugar in the can of soda the molar ma
vfiekz [6]

Explanation:

Given :

Amount of solute - sucrose (C12H22O11) = 41 g

Amount of solvent -soda  = 355-mL

Molarity of the solution with respect to sucrose= ?

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

               Molarity =  

Amount of solvent is given in mL, let’s convert to L :

               1 L = 1000 mL

Therefore, 355 mL in L will be :

                   

               = 0.355 L

We have the amount of solute in g, let’s calculate the number of moles first :

       Number of moles (n) =  

Molar mass of C12H22O11 = 342.29 g/mol.

Therefore, n =  

               = 0.119 moles.

8 0
3 years ago
Are the chemical reactions that take place when a battery connected endothermic or exothermic
Vilka [71]

Answer:

The answer is endothermic as the heat flows into the system from the surroundings. The products are at higher energy than the reactants, as they have absorbed energy.

8 0
3 years ago
1. A 225-L barrel of white wine has an initial free SO2 concentration of 22 ppm and a pH of 3.70. How much SO2 (in grams) should
Alexandra [31]

Answer:

The appropriate answer is "9.225 g".

Explanation:

Given:

Required level,

= 63 ppm

Initial concentration,

= 22 ppm

Now,

The amount of free SO₂ will be:

= Required \ level -Initial \ concentration

= 63-22

= 41 \ ppm

The amount of free SO₂ to be added will be:

= 41\times 225

= 9225 \ mg

∵ 1000 mg = 1 g

So,

= 9225\times \frac{1}{1000}

= 9.225

Thus,

"9.225 g" should be added.

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chubhunter [2.5K]

Answer:

Explanation:

The physical methods of separating mixtures are used in sorting a mixture of substances.

It requires no chemical changes occurring between their components and parts in any significant way.

Examples are:

  1. Decantation
  2. Filtration
  3. Sublimation
  4. Magnetism
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The methods simply relies on the physical properties of matter.

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