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MakcuM [25]
3 years ago
9

A bank loaned out ​$​12,00, part of it at the rate of 9% per year and the rest at 19% per year. If the interest received in one

year totaled ​$​1,500, how much was loaned at 9%
Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

$7,800 was invested at 9% and $4,200 at 19%.

Step-by-step explanation:

Given that a bank loaned out $ 12,000, part of it at the rate of 9% per year and the rest at 19% per year, if the interest received in one year totaled $ 1,500, to determine how much was loaned at 9% the following calculation must be performed:

12,000 x 0.09 + 0 x 0.19 = 1,080

10,000 x 0.09 + 2,000 x 0.19 = 1,280

8,000 x 0.09 + 4,000 x 0.19 = 1,480

7,900 x 0.09 + 4,100 x 0.19 = 1,490

7,800 x 0.09 + 4,200 x 0.19 = 1,500

Thus, $ 7,800 was invested at 9% and $ 4,200 at 19%.

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Step-by-step explanation:

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3 years ago
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X + y = 24
Masja [62]

Answer:

(10, 14)

Step-by-step explanation:

To solve this system let's use substitution:

Solve the first equation for x, obtaining x = 24 - y, and then substitute 24 - y for x in the second equation:

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Performing the indicated multiplication, we get:

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3 years ago
If it takes eight men ten hours to build a wall, how long would it take four men?
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