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sveta [45]
3 years ago
15

Amy performed an experiment in lab. She improperly mixed the chemicals, and an explosion of light, sound, and heat occurred. Whe

n Amy mixed the chemicals, energy was _______.
Chemistry
2 answers:
svlad2 [7]3 years ago
5 0

<span>The energy that was produced is called, heat combustion. It is an energy released in the form of heat when chemicals are mixed. An explosion of light and sound are the common characteristics of heat combustion. The chemical reaction takes place because of the presence of oxygen and hydrocarbon or organic molecule substances that when mixed form carbon dioxide and water which then releases heat and explosive characteristics.</span>

ElenaW [278]3 years ago
3 0

in other words the answer is transformed


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An aqueous solution was made by dissolving 72.9 grams of glucose, C6H12O6, into 115 grams of water. The vapor pressure of the pu
katen-ka-za [31]

Answer:

The correct answer is (d) 24.8 Torr

Explanation:

When a solute is added to a solvent, the water pressure of the solution is lower than the vapor pressure of the pure solvent. This is called <em>vapor pressure lowering</em> and it is given by the following expression:

Psolution= Xsolvent x Pºsolvent

We have to calculate Xsolvent (mole fraction of solvent) which is given by the number of moles of solute divided into the total number of moles.

First, we calculate the number of moles of solute and solvent. The solute is glucose (C₆H₁₂O₆), and its number of moles is calculated from the mass and the molecular weight (MM):

MM (C₆H₁₂O₆)= (12 g/mol x 6) + (1 g/mol x 12) + (16 g/mol x 6) = 180 g/mol

moles of glucose= mass/MM= (72.9 g)/)(180 g/mol)= 0.405 moles

The solvent is water (H₂O) and again we calculate the number of moles as follows:

MM(H₂O)= (1 g/mol x 2) + 16 g/mol = 18 g/mol

moles of water= mass/MM= (115 g)/(18 g/mol)= 6.389 moles

Now, we calculate the total number of moles (nt):

nt= moles of glucose + moles of water= 0.405 moles + 6.389 moles= 6.794 moles

The mole fraction of water (Xsolvent) is given by:

Xsolvent= moles of water/nt= 6.389 moles/6.794 moles= 0.940

Finally, the vapor pressure of water over the solution will be the following:

Psolvent= Xsolvent x Pºsolvent= 0.940 x 26.4 Torr= 24.8 Torr

8 0
3 years ago
This type of intermolecular force relates to the
creativ13 [48]
Hydrogen bonds are a special type of dipole-dipole attraction that results when hydrogen is bonded to one of the three most electronegative elements: F, O, or N.
3 0
2 years ago
The temperature of 500 mL of water is 16°C what happens to the water when thermal energy is transferred to it
Lunna [17]

Answer:

The temperature of the water increases because the average

kinetic energy of the water molecules increases.Explanation:

3 0
3 years ago
Solid potassium chlorate decomposes upon heating to form
olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of  oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

V2 = \frac{P1V1T2}{T1P2}

V2 = 664.1052 ml

245.2   yielded 67.2 molar volume of oxygen

0.66411 will yield = \frac{245.2 * 0.66411}{67.2}  = 2.4232 g

percentage of potassium chlorate in the original mixture = \frac{2.4232 * 100}{7.44} = 32.6%

3 0
3 years ago
Calculate the concentration, in moles per litre, of a solution formed when 13.0 g of calcium hydroxide is dissolved in 5.0 L. Pl
vichka [17]

Answer: The concentration, in moles per litre, of a solution formed when 13.0 g of calcium hydroxide is dissolved in 5.0 L is 0.036 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of Ca(OH)_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{13.0g}{74g/mol}=0.18mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.18}{5.0L}=0.036M

Therefore, the concentration, in moles per litre, of a solution formed when 13.0 g of calcium hydroxide is dissolved in 5.0 L is 0.036 M

8 0
3 years ago
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