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nexus9112 [7]
3 years ago
9

Examples of gravitational potential energy.

Chemistry
2 answers:
tia_tia [17]3 years ago
8 0
The equation for gravitational potential energy is GPE = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 on Earth), and h is the height above the ground in meters.
Dennis_Churaev [7]3 years ago
4 0

Answer:

the top of the roller coaster

Explanation:

the roller coaster at the top when it has the most potential energy reaches Peak when its going to convert into kinetic energy

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Answer: A

Explanation: Beta particles have a charge of -1

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Read 2 more answers
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LenaWriter [7]

Answer:

I say the second one, im not rlly sure tho

Explanation:

5 0
2 years ago
Hydrates that have a low vapor pressure and remove moisture from air are said to be ___. Question 8 options: effloresce hygrosco
-Dominant- [34]

Answer:

Hygroscopic

Explanation:

An hygroscopic substance is one that absorbs moisture from the atmosphere and becomes wet. Their ability to remove water from air is less than that of deliquescent substances. Most of the solid hygroscopic substances forms pasty substances and not solutions like the deliquescent compounds.

Examples are sodium trioxonitrate(v), copper(ii) oxide e.t.c

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4 0
3 years ago
The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (hooccooh) and must be removed before the st
Andrei [34K]
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2  so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄      ⇄     H⁺   + HC₂O₄⁻
0.0356 M            0          0
0.0356 - x            x          x
Ka1 = \frac{[H^+][HC2O4^-]}{[H2C2O4]} = x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6
5 0
3 years ago
22. A piece of wood board contains approximately 6.76 X 1023 molecules of wood, C2H4920, how
Licemer1 [7]

Answer:

<h2>1.23 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{6.76 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{6.76}{6.02}  \\  = 1.22923...

We have the final answer as

<h3>1.23 moles</h3>

Hope this helps you

5 0
3 years ago
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