Answer:
answer is the 2nd one
Step-by-step explanation:
y = 1/3(3) - 1 = 1 - 1 = 0 (3,0)
y = 1/3(0) - 1 = 0 - 1 = -1 (0, -1)
y= 1/3(6) - 1 = 2 - 1 = 1 (6, 1)
The measure of the angle ∠PQR is 90 degrees
<h3>How to prove that ∠PQR is 90 degrees?</h3>
The equation of the line PQ is given as:
3x - y - 2 = 0
The coordinates of the QR are given as:
(0, -2) and (6, -4)
Make y the subject in 3x - y - 2 = 0
y = 3x - 2
The slope of the above line is
m1 = 3
Next, we calculate the slope (m2) of points Q and R.
So, we have:
m2 = (y2- y1)/(x2 - x1)
This gives
m2 = (-4 + 2)/(6 - 0)
Evaluate
m2 = -1/3
The slopes of perpendicular lines are opposite reciprocals.
m1 = 3 and m2 = -1/3 are opposite reciprocals.
This means the lines PQ and QR are perpendicular lines.
The angle at the point of perpendicularity is 90 degrees
Hence, the measure of the angle ∠PQR is 90 degrees
Read more about linear equations at:
brainly.com/question/15602982
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Answer:
2ab(7a^4b^2+ a^5×b-2a)
start with multiple 2ab into the equation
(2ab×7a^4b^2)+(2ab×a^5×b)-(2ab×2a)
((2×7)a^(4+1)b^(2+1))+(2×a^(5+1)×b^(1+1))-((2×2)a^(1+1)×b)
14×a^5×b^3+2×a^6×b^2-4×a^2×b
Answer:
The correct answer is centimeter.
So the students are on 5:6 ratio from volleyball to football, and we know there are 220 students in total.
